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3 years ago

The probability that one bulb is red and one is yellow is

Mathematics

1 answer:

Paladinen [302]3 years ago

6 0

There are infinite possible answers for this. Provide more details or acceptable assumptions.

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Which of the following is a linear function?

Amiraneli [1.4K]

I got y = two over three x

6 0

3 years ago

Read 2 more answers

Hey can you please help me posted picture of question

Paladinen [302]

We have to take out the greatest common factor from the given polynomial to factorize the expression. If you observe the terms of the polynomial, the greatest factor that is common to all the terms is $4 x^{4}$ . So taking it out as common, the factorization of the polynomial will be:

$16 x^{9} -36 x^{5}-8 x^{4} \\ \\ 
=4 x^{4}(4 x^{5}-9x-2)$

So the option C gives the correct answer

7 0

3 years ago

PLEASE HELP ME!

Tatiana [17]

Answer:

TRUE

Step-by-step explanation:

2x + 0.8/y = z – 4

x = 7, y = 0.2, z = 22

2×7 + 0.8/0.2 = 22 - 4

14 + 4 = 18

18 = 18

TRUE.

6 0

3 years ago

Official unemployment rates for the U.S. population are reported on a monthly basis by the Bureau of Labor Statistics. For the p

Kitty [74]

Step-by-step explanation:

Clearly, there is a common difference between the monthly employment rates:

8.7% - 8.9% = -0.2%

8.5% - 8.7% = -0.2%

8.3% - 8.5% = -0.2%

a) So, for every month x, the percentage will go down 0.2%, starting at 8.9%. So, we can make this equation:

y = -0.2x + 9.1, where x = 1 would be October 2011.

January 2013 is 16 months after October 2011, so:

y = -0.2(16) + 9.1

y = 5.9%

b) To find when the unemployment rate will be zero, we set the equation equal to zero:

0 = -0.2x + 9.1

-0.2x = -9.1

x = 45.5 months

So, rounding up, the U.S. would reach a zero unemployment rate in 46 months or around September 2014? Not completely sure.

5 0

3 years ago

Looking at the two quadratic functions below (1 & 2), answer the following questions.

algol [13]

Part A:

Given parabola (1) to be $f(x) =-(x+12)^2 -6$ , and parabola (2) to be $f(x)=13(x-4)^2+1$

Notice that parabola (2) is stretched horizontally by a factor of 13 which is greater than 1. This means that parabola (2) is further away from the x-axis than parabola (1). (i.e. parabola (2) is more 'vertical' than parabola (1).

Therefore, parabola (1) is wider than parabola (2).

Part B:

A parabola open up when the coefficient of the quadratic term (the squared term) is positive and opens down when the coefficient of the quadratic term is negative.

Given parabola (1) to be $f(x) =-(x+12)^2 -6$ , and parabola (2) to be $f(x)=13(x-4)^2+1$

Notice that the coefficient of the quadratic term is positive for parabola (2) and negative for parabola (1), therefore, the parabola that will open down is parabola (1).

Part C:

For any function, f(x), the graph of the function is moved p places to the left when p is added to x (i.e. f(x + p)) and moves p places to the right when p is subtracted from x (i.e. f(x - p)).

Given parabola (1) to be $f(x) =-(x+12)^2 -6$ , and parabola (2) to be $f(x)=13(x-4)^2+1$

Notice that in parabola (1), 12 is added to x, which means that the graph of the parent function is shifted 12 places to the left while in parabola (2), 4 is subtracted from x, which means that the graph of the parent function is shifted 4 places to the right.

Therefore, the parabola that would be furthest left on the x-axis is parabola (1).

Part D:

For any function, f(x), the graph of the function is moved q places up when q is added to the function (i.e. f(x) + q) and moves q places down when q is subtracted from the function (i.e. f(x) - q).

Given parabola (1) to be $f(x) =-(x+12)^2 -6$ , and parabola (2) to be $f(x)=13(x-4)^2+1$

Notice that in parabola (2), 1 is added to the function, which means that the graph of the parent function is shifted 1 place up while in parabola (1), 6 is subtracted from the function, which means that the graph of the parent function is shifted 6 places down.

Therefore, the parabola that would be highest on the y-axis is parabola (2).

7 0

4 years ago