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Shkiper50 [21]
3 years ago
15

Kayla left a pile of gummy bears in the sun. After several hours 12 melted. This accounted for 40% of the total number. How many

gummy bears did she leave in the sun?
Mathematics
2 answers:
iris [78.8K]3 years ago
7 0
She left 30 gummy bears
abruzzese [7]3 years ago
7 0

Answer:

please find attached pdf

Step-by-step explanation:

Download pdf
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I need to find what x is G(21) = -3x + 3
ollegr [7]
Answer:

X= -7G + 1

Isolate the variable by dividing each side by factors that don’t contain the variable.
6 0
4 years ago
Roma selects cards from a standard of 52 cards. Once a card is selected, it is not replaced. Find the probability of each outcom
meriva

Given:

A card is selected randomly from a standard deck of 52 cards.

To find:

The probability of each outcome.

a. a king of heart

b. a queen of spades

c. an ace of flower

d. an ace of diamond​

Solution:

In a standard deck of 52 cards.

Total number of cards = 52

13 cards of each suit (heart, diamond, club, spade).

13 cards are Ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack, Queen, King.

a. We need to find the probability of getting a king of heart.

Number of king of heart = 1

P(\text{a king of heart})=\dfrac{\text{Number of king of heart}}{\text{Total cards}}

P(\text{a king of heart})=\dfrac{1}{52}

b. We need to find the probability of getting a queen of spades.

Number of queen of spades = 1

P(\text{a queen of spades})=\dfrac{\text{Number of queen of spades}}{\text{Total cards}}

P(\text{a queen of spades})=\dfrac{1}{52}

c. We need to find the probability of getting an ace of flower (spades).

Number of ace of flower = 1

P(\text{an ace of flower})=\dfrac{\text{Number of ace of flower}}{\text{Total cards}}

P(\text{an ace of flower})=\dfrac{1}{52}

d. We need to find the probability of getting an ace of diamond​.

Number of ace of diamond​ = 1

P(\text{an ace of diamond​})=\dfrac{\text{Number of ace of diamond​}}{\text{Total cards}}

P(\text{an ace of diamond​})=\dfrac{1}{52}

Therefore, the required probabilities for each parts are:

(a) \dfrac{1}{52}

(b) \dfrac{1}{52}

(c) \dfrac{1}{52}

(d) \dfrac{1}{52}

4 0
3 years ago
28.<br> Suppose y varies directly with x. If y = 3 when x = 2, find y when x = 3.
horrorfan [7]

Answer:

i wanna say it's 4

____________________

3 0
3 years ago
in 18 days, 20 workers can build a school. How many days would it take if there were only 12 workers?​
Marat540 [252]

To build a school;

20 workers -> 18 days.

So 1 worker -> 18/20 days.

So; 12 workers -> (12×18)/20 days.

-> (12×9)/10 days

->10.8 days.

so 10.8 days is your answer.

Hope it helps...

Regards;

Leukonov/Olegion

4 0
3 years ago
The starting numbers for x and y are already entered in a table below the blanks in the table represent the next two terms for e
Paul [167]

Answer:

it is this one

Step-by-step explanation:

because since x is 4 and y is 8 that one matches up better than any other one

6 0
3 years ago
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