Hello,
y=sin²(cos(2x))
y'=2*sin(cos(2x))*cos(cos(2x))*(-sin(2x)*2)
= -4*sin(cos(2x))*cos(cos(2x))*sin(2x)

Hence, value of x in the given equation is 2
Answer:
-20
Step-by-step explanation:
when you solve: -7u-7=7, you get u= -2 and when you plug it in you get this equation 9(-2)-2=?
then you get -20
Answer:
A, C, F
Step-by-step explanation:
JK is proportional to PQ, so that would be 8/x. Then, JL is proportional to PR, which would be 10/5. So, the answer is: 8/x = 10/5
Then, C would also be correct as KL is proportional to QR, and JK is proportional to PQ.
Finally, F is correct as JK to KL is proportional to PQ to QR, as JK is proportional to PQ, and KL is proportional to QR.