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Tju [1.3M]
3 years ago
11

What times 8 eguals 100

Mathematics
2 answers:
quester [9]3 years ago
5 0
100/ 8 = 12.5 so 12.5 * 8 = 100
ruslelena [56]3 years ago
3 0
just divide 100 by 8 and you get 12.5
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What is compression
zysi [14]

Answer:

the action of compressing or being compressed.

the reduction in volume (causing an increase in pressure) of the fuel mixture in an internal combustion engine before ignition.

Step-by-step explanation:

corona is real

7 0
3 years ago
In a recent poll, 778 adults were asked to identify their favorite seat when they fly, and 492 of them chose a window seat. Use
seropon [69]

Answer:

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

p_v =P(Z>7.36)=9.19x10^{-14}  

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

Step-by-step explanation:

1) Data given and notation

n=778 represent the random sample taken

X=492 represent the people that chose a window seat.

\hat p=\frac{492}{778}=0.632 estimated proportion of people that chose a window seat.

p_o=0.5 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the majority of adults prefer window seats when they fly:  

Null hypothesis:p \leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.632 -0.5}{\sqrt{\frac{0.5(1-0.5)}{778}}}=7.36  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>7.36)=9.19x10^{-14}  

5) Conclusion

Since the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of adults prefer window seats when they fly is significantly higher than 0.5 .  

6 0
3 years ago
PLEASE HELP!! (and show steps if u can)
Flauer [41]

Answer:

slope: -1

Step-by-step explanation:

Complete y2 - y1 over x2 - x1 with your given points.

-3 - (-1)  =  -2

_____     ___

2  -  0  =    2

= ⁻²⁄₂ = -1      Simplify to lowest term

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2 years ago
Martha took 48 pictures of flowers and 36 pictures of beautiful scenery.she wants to display the pictures so there are the same
Goshia [24]
Well if you have 48 pics of flowers and 36 pictures of scenery and you want an equal amount of pictures of the scenery, you want to start out by just seeing what number divides evenly into both, in this case, it is four.
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3 years ago
How do you calculate<br> heights of students in class
il63 [147K]

Answer:

To find the mean , median and mode of the students.

Step-by-step explanation:

The students choose from the three definitions of average to find the mean, median or mode of the students’ height in the school.

Students develop a strategy, collect and record data, and analyse data to answer this question.

The key concepts are

Consolidating the terms mean, median and mode.

The students should find the median of the height for the school if they have collected the median result of each grade.

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3 years ago
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