Find three consecutive odd integral such that the sum of seven times the smallest and twice the largest is -91
Answer:
7
Step-by-step explanation:
2^3 • 2^7 = 2^10
When multiplying exponents, the exponents add up together. In other words, just subtract 10-3 = 7 that would be your missing exponent!
Hope this helps, good luck!
Answer: 9
Step-by-step explanation:
