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trapecia [35]
2 years ago
14

Which table represents a proportional relationship that has a constant of proportionality equal to 0.8?

Mathematics
1 answer:
Andrej [43]2 years ago
5 0

Answer:

Column #1 - 0,5,10,12.5

Column #2 - 0.8

Step-by-step explanation:

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Share £180 in the ratio<br> 1:9
Schach [20]

Answer:

18:162

Step-by-step explanation:

1:9

1+9=10

(1×180)÷10= 18

(9×180)÷10=162

4 0
3 years ago
Find the percentage error |sinθ - θ|/sin(θ)*100 this approximation introduces for an angle of 0. 020 radians.
Elza [17]

Considering the given angle and the given formula, it is found that the percentage error for an angle of 0.02 radians is of 0.0067%.

<h3>What is the percentage angle for an angle?</h3>

For an angle \theta, it is given by the following formula:

P = 100\frac{|\sin{\theta} - \theta|}{\sin{\theta}}

In this problem, the angle is of \theta = 0.02, hence:

P = 100\frac{|\sin{0.02} - 0.02|}{\sin{0.02}}

P = 0.0067

The percentage error for an angle of 0.02 radians is of 0.0067%.

More can be learned about percent error at brainly.com/question/25224978

8 0
2 years ago
A model of a car is 4 inches long. If the actual car is 8 feet long, find the scale of the model. a. 4 in = 2 ft c. 8 in = 4 ft
Romashka-Z-Leto [24]

Answer:

1 inch = 2ft

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A sample of 11 students using a Ti-89 calculator averaged 31.5 items identified, with a standard deviation of 8.35. A sample of
lina2011 [118]

Answer:

We reject H₀, with CI = 90 % we can conclude that the mean numbers of times identified with Ti-84 does not exceed that of the Ti-89 by more than 1,80

Step-by-step explanation:

Ti-89 Calculator

Sample mean     x = 31,5

Sample standard deviation   s₂  = 8,35

Sample size        n₂ = 11

Ti-84 Calculator

Sample mean     y = 46,2

Sample standard deviation   s₁  = 9,99

Sample size        n₁ = 12

t(s)  = ( y - x - d ) / √s₁²/n₁ + s₂²/n₂

t(s)  = 12,9 / √(99,8/12) + (69,72/11)

t(s)  = 12,9 / √8,32 + 6,34

t(s)  = 12,9 / 3,83

t(s) = 3,37

Test Hypothesis

Null Hypothesis               H₀      y - x > 1,80

Altenative Hypothesis       Hₐ      y - x ≤ 1,80

We have a t(s) = 3,37

We need to compare with t(c)   critical value for

t(c) α; n₁ +n₂-2            df = 12 +11 -2     df  = 21

If we choose  CI = 95 %    then  α = 5 %   α = 0,05

From t-student table

t(c) = 1,72

t(s) = 3,37

t(s) >t(c)

t(s) is in the rejection region therefore we accept Hₐ with CI = 95 %

8 0
3 years ago
What is the completely factored form of the expression 16x2 + 8x + 32?
Pachacha [2.7K]
The app photo math is really awesome,
I Hope this Helps!

4 0
3 years ago
Read 2 more answers
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