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I am Lyosha [343]
4 years ago
6

Fright Night will be a bit different this year. Virtual tickets will cost 10 dollars for adults (a) and 5 dollars for kids(k). W

rite an algebraic expression that could describe how much you would have to pay for 3 adults and 7 kids?
Mathematics
2 answers:
Sliva [168]4 years ago
7 0

Answer:

10a+7k=c

10(3)+7(7)=79

Step-by-step explanation:

you substitute 3 for a because there are 3 adults.

then you substitute 7 for k because there are 7 kids.

you solve the equation and  get 79 the you substitute 79 for c because that is the cost for 3 adults and 7 kids.

blagie [28]4 years ago
6 0

Answer:

(10 x a) + (5 x k)

Step-by-step explanation:

If you were to solve this problem, this would be the process:

First, we need to plug in our values.

(10 x 3) + (5 x 7)

Next, we solve the multiplication.

30 + 35

Finally, the add the two remaining terms to get the total cost for both kid and adult tickets.

$65 would be the final answer.

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3 years ago
Which graph represents the function y = 3*+2?
puteri [66]

Answer:

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5 0
3 years ago
A business has $15,000 to spend on airline tickets to travel to a conference. It wants 27 of its employees to attend. The busine
marusya05 [52]

Answer:

<u>The correct answer is :</u>

<u>D. 700x + 375y = 15,000 </u>

<u>x + y = 27</u>

Step-by-step explanation:

1. Let's review the information given to answer the question correctly:

Budget for airline tickets = US$ 15,000

Number of employees attending the conference = 27

Price of business-class ticket = US$ 700

Price of economy-class ticket = US$ 375

2. Let's create a system of equations that models how many of each type of ticket the business should purchase.

x = Number of employees flying business-class

y = Number of employees flying economy-class

<u>x + y = 27 (Number of employees attending the conference)</u>

<u>700x + 375y = 15,000 (Cost of employees flying business plus cost of employees flying economy equal to budget for buying the airline tickets) </u>

3 0
3 years ago
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