All categories

3 years ago

I don't know how to do question 12(b)

Mathematics

1 answer:

Virty [35]3 years ago

5 0

Amy: x skirts Betty: 2x skirts Carol: (2x) + 7 skirts If Amy has 18 less than Carol, than Carol's equation minus 18 equals Amy's equation: [(2x) + 7] - 18 = x +18 +18 (2x) + 7 = x + 18 - 7 -7 2x = x + 11 -x -x x = 11 Input the solution for x into the girls equation to double check. Amy: 11 Betty: 2(x) 2(11) =22 Carol: (2x) + 7 22 + 7 =29 Does Amy have 18 less than Carol? Carol - Amy = 18 29 - 11 = 18 18 = 18 the problem is solved

You might be interested in

!!!!!!!!!help pleaseeeeeee

Elden [556K]

Cause AB = CD so

answer is D.
arc AB = arc CD

8 0

3 years ago

What is an equation of the line that passes through the points (-8, 2) and (-4, -3)?

denpristay [2]

Answer:

y = (-6/13)x + (4/13).,

Step-by-step explanation:

the equation of the line is:

y = mx + b, where "m" is the slope and "b" gives the y-intercept

m = (y2 - y1)/(x2 - x1)

m = (-2 - 4)/(5 - (-8))

m = -6/13

y = (-6/13)x + b

the line passes through the point (-8,4) means that for x = -8, y = 4

4 = (-6/13)(-8) + b

b = 4 - (-6/13)(-8)

b = 4/13

the equation of the line that passes through the points (-8,4) and (5,-2) is:

y = (-6/13)x + (4/13).

5 0

3 years ago

Solve: ( 6 1/5+2 1/2) x 0.85

QveST [7]

It's 21.125 hope this works good luck ;)

6 0

3 years ago

Read 2 more answers

A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard

Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

$\sigma=\frac{0.8}{\sqrt{37}}=0.13$

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

$z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69$

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, $P(z > 1.69) = 1 - P(z < 1.69)$

$P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%$

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0

3 years ago

Simplify the expression. <br> 100^(1/2)-125^(1/3)<br> PLEASE HELP OFFERING 24 POINTS

Alecsey [184]

Type it into Google and it will solve for you.

100^(1/2)-125^(1/3) = 10-5 = 5

5 0

3 years ago