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Ivanshal [37]
3 years ago
13

A right triangle has legs that are 11 inches and 13 inches long what is the area of the triangle

Mathematics
1 answer:
blsea [12.9K]3 years ago
7 0
143 the i answer is 143

hope this helps
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Men im mainly talking to you....
andreyandreev [35.5K]

are in that situation pls tell me

6 0
3 years ago
Graph this inequality:<br> y ≤ 1/4x
Leviafan [203]
Graph this inequality:

8 0
2 years ago
[4 - (3c - 1)][6 - ( 3c - 1)]
Anestetic [448]
Hi there!

You would have to simplify the terms inside [ ] this thing, then multiply.

So let's simplify them first.

4 - (3c - 1) 
use distributive property.....
4 - 3c + 1
-3c + 5

6 - (3c - 1)
use distributive property again...
6 - 3c + 1
-3c + 7

so now, multiply (-3c + 5)(-3c + 7).
(-3c + 5)(-3c + 7)
9c² - 21c - 15c + 35
9c² - 36c + 35

So your final answer is...
9c² - 36c + 35

Hope this helped! :)
3 0
3 years ago
Read 2 more answers
Please help with the graph
tamaranim1 [39]
This is the answers

5 0
3 years ago
Read 2 more answers
If a ball is thrown directly upward with a velocity of 50ft/s, it's height (in feet) after t seconds is given by y=50t-16t^2 wha
Tomtit [17]

Answer:

39.0625 ft

Step-by-step explanation:

Since the function is a quadratic representing height, and the coefficient of the t² is negative, the vertex of the parabola will be the maximum height achieved by the ball.  

The general form for a quadratic equation is ax² + bx + c, here a is -16, and b is 50

To find the x coordinate of the vertex, use   x = -b/(2a)

We have x = -50/[2(-16)]

               

                  x = -50/-32

             

                         x= 25/16

Now plug that into the equation to find the y value, which will be the height...

y = 50(25/16) - 16(25/16)²

    y = 1250/16 - 16(625/256)

        y = 1250/16 - 625/16

              y = 625/16

                   y = 39.0625

7 0
3 years ago
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