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Paha777 [63]
3 years ago
5

Which expression is the simplest form -(4x^3+x^2)+2(x^3-3x^2)

Mathematics
1 answer:
Anit [1.1K]3 years ago
4 0

Answer:

6x^3-5x^2

Step-by-step explanation:

(4x^3+x^2)+2(x^3-3x^2)

4x^3+x^2+2x^3-6x^2

4x^3+2x^3+x^2-6x^2

6x^3+x^2-6x^2

6x^3-5x^2

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Sue wants to plan a meal with 71 grams of fat and 1755 calories. If hot dogs have 13 grams of fat and 145 calories each and if b
Lena [83]

Answer:

Sue must use 3 hotdogs and 4 half-cup serving of baked beans.

Step-by-step explanation:

Let the number of hot dogs be represented by h

Let the number of baked beans be represented by b

Hot dogs have 13 grams of fat and 145 calories each

Baked beans have 8 grams of fat and 330 calories per half cup serving

Sue wants to plan a meal with 71 grams of fat and 1755 calories.

Grams of Fat from Hotdog + grams of fat from baked beans=71

13h+8b=71....(I)

Similarly,

Calories from hot dog + Calories from baked beans=1755

145h+330b=1755....(II)

We then solve Equations (I) and (II) simultaneously.

13h+8b=71....(I)

145h+330b=1755....(II)

Multiply equation 1 by 145 and equation 2 by 13

1885h+1160b=10295

1885h+4290b=22815

Subtracting

-3130b=-12520

b=4

Substitute b=4 into (I)

13h+(8X4)=71

13h=71-32

13h=39

h=3

Sue must use 3 hotdogs and 4 half-cup serving of baked beans.

4 0
4 years ago
Write an expression equivalent to 8(3/4x-1/4)-6(12-x) using the fewest possible terms.
Harrizon [31]
Use distributive property: (24/4x-8/4)-(72-6x)
Simplify: 6x-2-72+6x
Simplify: 12x-74

12x-74
3 0
3 years ago
What proportion of US women have a height greater than 69.5 inches?
kiruha [24]

Using the Normal distribution, it is found that 0.0359 = 3.59% of US women have a height greater than 69.5 inches.

In a <em>normal distribution</em> with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

US women’s heights are normally distributed with mean 65 inches and standard deviation 2.5  inches, hence \mu = 65, \sigma = 2.5.

The proportion of US women that have a height greater than 69.5 inches is <u>1 subtracted by the p-value of Z when X = 69.5</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{69.5 - 65}{2.5}

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

1 - 0.9641 = 0.0359

0.0359 = 3.59% of US women have a height greater than 69.5 inches.

You can learn more about the Normal distribution at brainly.com/question/24663213

3 0
3 years ago
Is number 3 correct and please explain ?
Paraphin [41]
Your correct, +1 would give you one point on y line then go down and over to get your slope, so yes you are correct, good job.
5 0
3 years ago
If 6 pears and 5 oranges cost $1.87 and 12 pears and 2 oranges cost $1.90, how much would 3 pears and 3 oranges cost?
Artyom0805 [142]
I'm going to do elimination to find the price of one pear and one orange.
6p +5o =1.87
12p + 2o=1.90
I'm going to multiply the first equation by -2.
-12p-10o = -3.74
12p + 2o =1.90
-8o= -1.84
-1.84÷ -8= .23= o
12p + 2 (.23) = 1.90
12p + .46 = 1.90
12p = 1.44
p=.12
A pear equals .12, while an orange equals .23.
3×.12= .36
.23× 3 = .69
.69 + .36 = 1.05
It would cost $1.05.
4 0
3 years ago
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