Question

e). Click the "draw structure" button to launch the drawing utility.Write a structural formula for the principal organic product formed in the reaction of methyl bromide with NaOH (sodium hydroxide). Click the "draw structure" button to launch the drawing utility.

Answer 1

Answer:

Methanol is produced as product of the reaction.

Explanation:

Methyl bromide contains a good leaving group $Br^{-}$ because of high polarizability of Br atom and weak C-Br bond.

$OH^{-}$ is a strong base as well as strong nucleophile due to small size and high electronegativity of oxygen atom.

Here methyl bromide primarily acts as an electrophile instead of an acid because of it's very weak acidity.

So, $OH^{-}$ acts as nucleophile towards methyl bromide by replacing bromide ion and forms methanol.

Reaction goes through $S_{N}2$ mechanism.

Structure formula of product has been given below.