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Mnenie [13.5K]
3 years ago
5

Simplify: –7(x – y – 2z)

Mathematics
1 answer:
Nady [450]3 years ago
3 0
I hope this helps you




-7x+7y+14z
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Solve the logarithmic equation with Properties of Logs
Rufina [12.5K]

Answer:

Simplifying

logx + -4 = 0

Reorder the terms:

-4 + glox = 0

Solving

-4 + glox = 0

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Add '4' to each side of the equation.

-4 + 4 + glox = 0 + 4

Combine like terms: -4 + 4 = 0

0 + glox = 0 + 4

glox = 0 + 4

Combine like terms: 0 + 4 = 4

glox = 4

Divide each side by 'lox'.

g = 4l-1o-1x-1

Simplifying

g = 4l-1o-1x-1

4 0
3 years ago
Read 2 more answers
Solve the inequality x divided by 6 is less than or equal to 3
Alja [10]
Your inequality looks like this:
\frac{x}{6}  \leq 3
To get rid of the /6, you need to multiply by 6 as the opposite operation cancels it out. So, all you need to do is multiply both sides by 6 to isolate x. 
Therefore:
x \leq 18
6 0
3 years ago
The temperature was −10 °F and dropped by 16 °F. Which statement represents the resulting temperature in degrees Fahrenheit? A −
algol13
<span>A
−10 + 16 = 6
........................................................</span>
5 0
4 years ago
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The ratio of tom’s age to Mary’s is 3:4.If Tom is 15 how old is Mary
AnnZ [28]
Hey there!

Tom's age to Mary's is 3:4; an equivalent ratio is 15:x (x symbolizes Mary's age).

To solve for this, we need to divide our proportions. By that, I mean divide Tom's older age by his younger age. If we do so, we should get a scale factor that we can multiply Mary's younger age by.

15 / 3 = 5

This means that the scale factor of the ages is 5.

x / 4 = 5 (Solving for Mary's unknown age.)

To solve for x, multiply both sides by 4.

x/4 * 4 = x
5 * 4 = 20

x = 20

Mary's age is 20.

I hope this helps!
3 0
3 years ago
Justin made 184 for 8 hours of work. At the same rate, how many hours would he have to work to make 115?
Kisachek [45]

Answer:

8/184

0.0434782609x115

5

Step-by-step explanation:

5

7 0
3 years ago
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