it would be b or c depending on a's number
The problem can be translated into an equation that is something like 4/5 + 3/x = 1/2
we cannot have x equal to zero because the number can be infinite.
So the LCD here is 10x, so multiply both sides by that to get:
8x + 30 = 5x
Subtract 5x and 30 from both sides:
3x = -30
divide:
x = -10
The solution isn't zero so there is a solution.
Left
because -8.85<8.8, small numbers goes to the left while larger ones go to the right
For a rectangle, A = LW.
A = (3x + 2)(x - 4)
A = 3x^2 - 12x + 2x - 8
A = 3x^2 -10x - 8
1y - 1/x = 1/60 = x*y =60 = x=60/y
3y - 2(60/y) = 6
3y^2-120=6y
3(y^2-40-2y) =0
y^2-40-2y=0
y = 7.4
3(7.4)-2x=6
22.2-2x = 6
2x = -16.2
x = -8.1
