Answer:
yea
Step-by-step explanation:
cuz then there would be a graph and stuff and you would analyze which student spends more time
(2x-3y=-4)-2(x+3y=7)
2x-3y-2x-6y=-4-14
-9y=-18
y=2, making x+3y=7 become:
x+6=7
x=1
So the solution to the system of equations is the point (1,2)
200 miles
$71-$35=$36 left in budget
$36/.18 per mile= 200 miles
Answer:
36 degrees
Step-by-step explanation:
since, m<AOB is a right angle, we shall just create an equation:
M<AOB+M<BOC=90 degrees
Substitute: 6z-12+3z+30=90
Solve: 6z+3x=9z
-12+30=18
so, 9z+18=90 degrees
-18 -18
9z=72
z=8
So if z=8, then we should fit it so that it matches measure of AOB.
6z-12
6 times 8=48
48-12= 36
<h3>
Answer: -15 and 2</h3>
You find this through trial and error.
A much more efficient way is to solve x^2-13x-30 = 0 using the quadratic formula. You'll find the two solutions to be x = 15 and x = -2
Going from those solutions, we get x-15 = 0 and x+2 = 0 which then turn into (x-15)(x+2) = 0 through the zero product property.
