K^2+8k-9=0 can you help me solve with showing work

2 answers:

7 0

Using the PSN method:

P = -9
S = 8
So N = 9,-1

Using 9 and -1 in the original equation gives:

$k^2+9k-k-9=0
\\k(k+9)-1(k+9)=0
\\(k-1)(k+9)

\\\\k=1,-9$

erastova [34]3 years ago

5 0

K² + 8k - 9 = 0
k = -8 +/- √(8² - 4(10)(-9))
 2(1)
k = -8 +/- √(64 + 360)
 2
k = -8 +/- √(424)
 2
k = -8 +/- 20.59126028
 2
k = -8 + 20.59126028 k = -8 - 20.59126028
 2 2
k = 12.5912608 k = -20.5912608
 2 2
k = 6.2956304 k = -10.2956304

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Evaluate the step function for the given input values. g(x) = g(2) = g(–2) = g(5) =

romanna [79]

Answer:

Step-by-step explanation:

g(2) = g(–2) = g(5) is never true for the step function. One " = " symbol per pair of g values, please.

The step function, which you're calling "g(x)," is 0 from -infinity up to but not including 0. It's 1 from x just greater than 0 through infinity.

Thus:

g(2) = 1 because x is greater than 0.

g(-2) = 0 because x is less than 0.

g(5) = 1 because x is greater than 0.

4 0

3 years ago

Which is the completely factored form of 4x3 10x2 – 6x? 2(x 3)(2x – 1) 2x(x 3)(2x – 1) 2x(x – 3)(2x – 1) 2(x – 3)(2x 1).

Natalija [7]

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Option B represents the correct factors of the equation.

<h3>What is a Factor of the number?</h3>

A factor of the number can be defined as a divisor of the number that divides it completely without leaving any remainder.

Given equation is 4x^3+10x^2 – 6x. This can be factorized as given below.

$4x^3+10x^2-6x = 0$