Answer:
When t=2.1753 & t=.5746 , h=27
Don't worry, I got you. Also, my calculator does too.
We set h equal to 27, because we want the height to be 27 when we solve for t.
That leaves us with:
27 = 7 + 44t - 16t^2
Simplify like terms,
20 = 44t - 16t^2
Move 20 onto the right side, so we can use quadratic equation
44t - 16t^2 - 20 = 0 --> -16t^2 + 44t - 20
Using quadratic, you get
t=2.1753 & t=.5746
<u>poster confirmed : "It’s t=2.18 and t=0.57"</u>
Answer:
2< AC<8
Step-by-step explanation:
For a triangle to exits sum of two sides must always be greater than the the third side
⇒ AC< AB+ BC =5+3=8 in
⇒AC<8 in
Also, the difference of the two sides must be smaller than the length of third side
⇒ AC> | AB-BC| = |5-3| =2
AC> 2 in
therefore, we can say 2< AC<8. Hence, AC can takes 3,4,5,6 values
Answer: The answer is 16.
Step-by-step explanation:
The least common denominator means the same as least common multiple.
3, 6, 9, 12, 16
8, 16
2, 4, 6, 8, 10, 12, 14, 16
Answer:
nothing
Step-by-step explanation:
You get nothing because it would make -43256742984
Answer:
Step-by-step explanation:
The genral form of a complex number in rectangular plane is expressed as z = x+iy
In polar coordinate, z =rcos ∅+irsin∅ where;
r is the modulus = √x²+y²
∅ is teh argument = arctan y/x
Given thr complex number z = 6+6√(3)i
r = √6²+(6√3)²
r = √36+108
r = √144
r = 12
∅ = arctan 6√3/6
∅ = arctan √3
∅ = 60°
In polar form, z = 12(cos60°+isin60°)
z = 12(cosπ/3+isinπ/3)
To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)
z^1/4 = 12^1/4(cosπ/12+isinπ/12)
When n = 1;
z1 = 12^1/4(cosπ/3+isinn/3)
z1 = 12^1/4cis(π/3)
when n = 2;
z2 = 12^1/4(cos2π/3+isin2π/3)
z2 = 12^1/4cis(2π/3)
when n = 3;
z2 = 12^1/4(cosπ+isinπ)
z2 = 12^1/4cis(π)
when n = 4;
z2 = 12^1/4(cos4π/3+isin4π/3)
z2 = 12^1/4cis(4π/3)
