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olga nikolaevna [1]
4 years ago
14

What is the recursive rule for the sequence?

Mathematics
1 answer:
adoni [48]4 years ago
5 0
An= -2 (an+1), a1 = 5
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Given f of x is equal to the quantity x minus 4 end quantity divided by the quantity x squared plus 13x plus 36 end quantity, wh
gavmur [86]

The simplified expression of the function f(x) =\dfrac{x-4}{x^2+13x+36} is

f(x) = \dfrac{x-4}{(x+9)(x+4)}. f(x) is increasing for all x > –4.The correct answer is option C.

<h3>What is a function?</h3>

A function is defined as a relation between the set of inputs having exactly one output each.

The function expression is given as:

f(x) =\dfrac{x-4}{x^2+13x+36}

Expand the denominator

f(x) =\dfrac{x-4}{x^2+4x +9x+36}

Factorize the denominator

f(x) =\dfrac{x-4}{x(x+4)+9(x+4)}

Factor out x + 9

f(x) = \dfrac{x-4}{(x+9)(x+4)}

The simplified expression of the function f(x) =\dfrac{x-4}{x^2+13x+36} is

f(x) = \dfrac{x-4}{(x+9)(x+4)}. f(x) is increasing for all x > –4

Read more about functions at:

brainly.com/question/1851758

#SPJ1

8 0
2 years ago
A 16-ounce bottle of shampoo costs $4.69. What is the price per ounce, rounded to the nearest cent?
Leto [7]

What is the price per ounce, rounded to the nearest cent? $0.29.

5 0
3 years ago
Read 2 more answers
What is the factorization of this polynomial? 9x^2-0x-4
Harman [31]
9x²-0x-4
=9x²-4
=(3x-2)(3x+2) is the factor form of 9x²-0x-4
Solve for x:
3x-2=0
Add 2 to each side
3x-2+2=0+2
3x=2
Divided 3 to each side
3x/3=2/3
x=2/3
Or
3x+2=0
Subtract 2 to each side
3x+2-2=0-2
3x=-2
Divided 3 to each side
3x/3=-2/3
x=-2/3. Hope it help!
5 0
3 years ago
You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal mass (3,000 kg each)
Kazeer [188]

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1, v_1 = = 20 m./s

Velocity of the truck 2,v_2 = 35 m./s

1. Kinetic energy of the truck 1:\frac{1}{2}mv_{1}^2=\frac{1}{2}\times 3000 kg\times (20 m/s)^=600,000 joules

Kinetic energy of the truck 2:\frac{1}{2}mv_{2}^2=\frac{1}{2}\times 3000 kg\times (35 m/s)^=1,837,500 joules

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height = mgh=3000\times 9.8 m/s^2\times 22 m=646,800 Joules

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

3 0
4 years ago
The marks scored by a group of students in English examination are as follows: 30,32, 33, 31, 32, 33, 34, 35, 33, 34 . Find the
Alecsey [184]

Answer:

Answer is 32

Step-by-step explanation:

Mode = no of stu +1/2

Mode =12+1/2

Mode =13/28=6.5

Mode =6th mark +7th mark /2

Mode=32+32/2

Mode=64/2

Mode=32

Hope it helps

Peace

Please mark me as brainliest

8 0
3 years ago
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