6a-3b^2-a+b-4+7a^2
goup like terms
7a^2-3b^2+6a-a+b-4
7a^2-3b^+5a-4
Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
Answer:
Make a coordinate plane and you have to solve around the origin say 4,4 and 4,1.
Step-by-step explanation:
x+4
___________
(x+2)|(x^2+6x+9)
-x^2-2x
__________
4x+9
-4x-8
__________
1
so the quotient is:
(x+2)(x+4)+1/(x+2)
It’s 54 because I did the math to get the answer
