Answer:
Step-by-step explanation:
for two lines to be parallel they MUST have the same slope but have different Y intercepts ( Y axis crossing values)
parallel lines will never intersect each other
first I use a graphing calcuator to solve the problem
I like to use y intercept form better, but you don't have use it 
I will try to solve it directly without going through the y intercept equation
x + 5y = 10    in y intercept form y = mx + b is 
5y = -x + 10     divide both sides by 5
y = -x/5 + 10/5     
y = -x/5 + 2 
Now I need to find a parallel line that passes through the x =1 and y = 3 point recall this line will have the same slope =     m = -1/5 
and a different Y axis crossing point 'b' that we don't know
y = -x/5 + b      y = 3 when x = 1 so slove for 'b'
3 = -1/5 + b
3 = -0.2 + b    add -0.2 to both sides
3.2 = b
y = -x/5 + 3.2     this is answer in y intercept form
                           if you multiply both sides by 5
5y = -x + 16        add x to both sides
x + 5y = 16         answer in standard form
THE EASIER WAY TO SOLVE THE PROBLEM IS ......
x + 5y = 10      find a line parallel that passes through x  = 1,  y = 3  
x + 5y = Z       Z is an unknown value  plug in x and y and solve for Z
1 + 5(3) = Z
Z = 16              so the parallel line in standard form is
x + 5y = 16     
same as before,  my y intercept method was correct, but not  worth the effort