= $\frac{24x^{5} }{4x^{2} }$ - $\frac{8x^{4} }{4x^{2} }$ + $\frac{12x^{3} }{4x^{2} }$ - $\frac{4x^{2} }{4x^{2} }$ ..........................separate the terms

= 6 $x^{5-2}$ - 2 $x^{4-2}$ + 3 $x^{3-2}$ - 1 ................ subtract the power of x from denominator

= 6 $x^{3}$ - 2 $x^{2}$ + 3 $x$ -1

= 2 $x^{2}$ ( 3 $x$ -1 ) + (3 $x$ -1 )................................... Take (3 $x$ -1 ) common in (6 $x^{3}$ - 2 $x^{2}$ )

= (3 $x$ -1 ) (2 $x^{2}$ +1) .......................................Take (3 $x$ -1 ) common in whole equation

3 0

3 years ago

Find the measure of the exterior angle 1. with one angle is 50 degrees and 28 degrees

OLga [1]

Answer:

D. 78°

Step-by-step explanation:

50°+28°= 78°

_______

3 0

2 years ago

The diagram shows a sector of a circle radius 10 cm. the angle is 135 degrees

Black_prince [1.1K]

Answer:

The perimeter is 43.6 cm

Step-by-step explanation:

In this question, we are tasked with calculating the perimeter of the sector.

Firstly, we define what a sector is. A sector is part of a circle which is is blinded by two radii and an arc. Hence we say a sector contains two radii.

Thus, to calculate the perimeter of the sector, we need the length of the arc added to 2 * length of the radius

Let’s calculate the length of the arc.

Mathematically, this is theta/360 * 2 * pi * r

where theta is the angle subtended at the middle of the circle which is 135 according to the question, and our radius is 10cm

Thus, we have

135/360 * 2 * 22/7 * 10 = 23.57 cm

Adding two radii to this, we have;

23.57 + 2(10)

= 23.57 + 20 = 43.57 = 43.6 cm to 1 decimal place

5 0

2 years ago