What is the function of f(g(x)) if f(x)= x^2+1 and g(x)=3x
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After 24 hours, 35.4% of the initial dosage remains on the body.
<h3>What percentage of the last dosage remains?</h3>
The exponential decay is written as:
Where A is the initial value, in this case 2.8mg.
k is the constant of decay, given by the logarithm of 2 over the half life, in this case, is:
Replacing all that in the above formula, and evaluating in x = 24 hours we get:
The percentage of the initial dosage that remains is:
If you want to learn more about exponential decays:
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