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2 years ago

A number with more than one dight?

Mathematics

2 answers:

Hatshy [7]2 years ago

8 0

The answer is 11 that is one more than one digit.

11Alexandr11 [23.1K]2 years ago

6 0

10
11
12
13
14
15
16
17
18
19
20
etc....

If I misunderstood your question, could you rephrase it in the comments?

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Susan's fish tank has 16 liters of water in it. She plans to add 4 liters per minute until the tank has at least 64 liters. What

Stolb23 [73]

Answer:

Step-by-step explanation:

cause I did it in classs

3 0

2 years ago

Jon makes a mix of salad that cost $15 using as much apples that cost $4/kg as oranges that cost $6/kg. How much of each fruit i

marysya [2.9K]

Let
x = number of apples.
y = number of oranges.
we have to write the following equation to represent the problem:
4x + 6y = 15
To satisfy the equation, Jon must have used
x = 2.25
y = 1
Substituting
4 (2.25) +6 (1) = 15
9 + 6 = 15
answer
Jhon used 2.25kg of apple and 1kg of orange to make the salad.
Note: Since the problem does not have any other restrictions, there may be several apple and orange combinations that cost $ 15 per salad.

6 0

2 years ago

Read 2 more answers

What is the exponential form of 100000

Yanka [14]

Answer:

10^4

Step-by-step explanation:

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

7 0

2 years ago

What is 9 times 52 using mental math property

arsen [322]

Everyone works differently in mental meth.

To calculate 9*52, we note that 9=10-1, so mentally calculate
9(52)
=(10-1)(52)
=520-52 [ subtract 20 from each number]
=(520-20)-(52-20)
=500-32
=468.

Alternatively,
9*52=9*50+9*2=450+18=468

If you're good with multiplication and division,
9*52=3*3(52)=3*156=450+18=468

3 0

3 years ago