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Brilliant_brown [7]
3 years ago
7

Is the statement 2(3+5x)=6+5x always true?

Mathematics
2 answers:
mihalych1998 [28]3 years ago
5 0
No that statement is not always true. There is only one solution to this equation.
charle [14.2K]3 years ago
5 0

Answer:No

Step-by-step explanation:

2(3+5x) = 6+5x

or, 6+10x = 6+5x

or, 10x = 5x

or, 2x = x ( only true for x = 0 )

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Schach [20]
The answer would be c
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What is y+4=9 what is y?
amid [387]

Answer:

y = 5

Step-by-step explanation:

Subtract the 4 from 9

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yKpoI14uk [10]

y =  \frac{7}{5} x + 1
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64 = 4(p + 2) + 24 please solve step by step
Wittaler [7]

Answer:

8

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   1 • -16 = -16

Step-2 : Find two factors of  -16  whose sum equals the coefficient of the middle term, which is   6 .

     -16    +    1    =    -15

     -8    +    2    =    -6

     -4    +    4    =    0

     -2    +    8    =    6    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  8

                    p2 - 2p + 8p - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

                   p • (p-2)

             Add up the last 2 terms, pulling out common factors :

                   8 • (p-2)

Step-5 : Add up the four terms of step 4 :

                   (p+8)  •  (p-2)

            Which is the desired factorization

3 0
3 years ago
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If x+1/x = 5 find the value of x^3 +1/x^3. pls solve​
Korolek [52]

Answer:

1) solve x+1/x = 5

\frac{x + 1}{x}  = 5

x + 1 = 5x

x - 5x =  - 1

- 4x =  - 1

x =  \frac{ -1}{ - 4}

x =  \frac{1}{4}

2) solve x³+1/x³

x {}^{3}  +  \frac{1}{x {}^{3} }

substitute x = 1/4 into the expression

( \frac{1}{4} ) {}^{3}  +  \frac{1}{( \frac{1}{4}) {}^{3}  }

\frac{1}{64}  +  \frac{1}{ \frac{1}{64} }

\frac{1}{64}  +  \frac{64 \times 1}{1}

\frac{1}{64}   + 64

\frac{4097}{64}  \: or \: 64.02

5 0
3 years ago
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