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dmitriy555 [2]
3 years ago
15

Does anyone know this one?

Mathematics
1 answer:
butalik [34]3 years ago
5 0

Answer:

C

Step-by-step explanation:

For the lines to be parallel, then the 2 given angles are alternate and congruent, thus

15x - 46 = 9x + 8 ( subtract 9x from both sides )

6x - 46 = 8 ( add 46 to both sides )

6x = 54 ( divide both sides by 6 )

x = 9 → C

You might be interested in
Find the substance's half-life, in days.<br> Round your answer to the nearest tenth.
shutvik [7]

Answer:

t = 5.6 day

t =5 days 14 hours 24 minutes

Step-by-step explanation:

Half life is the time it will take for the original value or quantity I'd a particular substance to decrease by half of it's original self.

N = N•e(-kt)

N• = 25

K = 0.1229

Then

N = 25/2 = 12.5

The reason because at the half life , it's original value will decrease to half.

Let's solve for the half life t

N = N•e(-kt)

12.5 = 25e(-0.1229t)

12.5/25 = e(-0.1229t)

0.5 = e(-0.1229t)

In 0.5 =-0.1229t

-0.69314 = -0.1229t

-0.69314/-0.1229 = t

5.6399 = t

To the nearest tenth

5.6 days = t

4 0
4 years ago
Please help me<br><br><br>3x - 12y = 60 <br><br>x + 2y = 14<br><br>will mark brainliest
Setler79 [48]

Answer:

x = 8, y = 3

Step-by-step explanation:

3x - 12y = 60

x + 2y = 14

3x - 12y = 60

3x + 6y = 42 (multiply by 3 so the x is the same as the top equation)

6y = 18 (subtract the equations)

y = 18 / 6

= 3

To find x, substitute y into the 2nd equation since it is the simplest so:

x + 2(3) = 14

x + 6 = 14

x = 14 - 6

= 8

7 0
3 years ago
After a long study, tree scientists conclude that a eucalyptus tree will grow at the rate of 0.5 6/ (t+4)3 feet per year, where
kipiarov [429]

Answer:

<h2>a) 0.5367feet</h2><h2>b) 0.5223feet</h2><h2>c) 0.7292feet</h2>

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

\int\limits {0.5 + \frac{6}{(t+4)^{3} }  } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} }  } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \  where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C

a)  The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from  t =1 to t = 2

\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\   = 0.9167 - 0.5 + 0.12\\= 0.5367feet

b)  The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from  t =2 to t = 3

\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\  = 1.439 - 0.9167\\= 0.5223feet

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} }  } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\   = 0.9167 - 0.1875\\= 0.7292feet

8 0
3 years ago
Find the solutions to x⁴-5x²-36=0 and the x-intercepts of the graph of y=x⁴-5x²-36.
disa [49]

Answer:

The solutions x^4-5x^2-36=0 are x=3,\:x=-3,\:x=2i,\:x=-2i and the x-intercepts of y=x^4-5x^2-36 are x=3,\:x=-3

Step-by-step explanation:

Finding the solutions to x^4-5x^2-36 means finding the roots, a root is where the function is equal to zero.

The x-intercept is the point at which the graph crosses the x-axis. At this point, the y-coordinate is zero.

To find the roots you need to:

Rewrite the equation with u=x^2 and u^2=x^4

u^2-5u-36=0

Solve by factoring

\mathrm{Break\:the\:expression\:into\:groups}\\u^2-5u-36=\left(u^2+4u\right)+\left(-9u-36\right)

\mathrm{Factor\:out\:}u\mathrm{\:from\:}u^2+4u=u\left(u+4\right)

\mathrm{Factor\:out\:}-9\mathrm{\:from\:}-9u-36=-9\left(u+4\right)

u^2-5u-36=u\left(u+4\right)-9\left(u+4\right)

\mathrm{Factor\:out\:common\:term\:}u+4\\\left(u+4\right)\left(u-9\right)

u^2-5u-36=\left(u+4\right)\left(u-9\right)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions to the quadratic equation are:

\:u=-4,\:u=9

Substitute back u=x^2, solve for x

x^4-5x^2-36=(u-9)(u+4)=(x^2-9)(x^2+4)

Apply the difference of squares formula

x^4-5x^2-36=(x^2-9)(x^2+4)=(x-3)(x+3)(x^2+4)

(x-3)(x+3)(x^2+4)=0

Using the Zero factor Theorem: if ab = 0 then a = 0 or b = 0 (or both a = 0 and b = 0)

The solutions are:

\:x=3,\:x=-3,\:x=2i,\:x=-2i

Because two of the solutions are complex roots the only x-intercepts are x=3,\:x=-3

3 0
3 years ago
5 less than 4 times a number is the same as 9 times the number.
cluponka [151]

Hi, there.

 _____

"5 less than 4 times a number" 4x-5

"is the same as" =

"9 times the number" 9x

Putting the parts together,

\boldsymbol{4x-5=9x}

Solving the two step equation

\boldsymbol{4x-9x=5}

\boldsymbol{-5x=5}

Divide both sides by -5

\boldsymbol{x=-1}

So the A answer checks.

Hope the answer - and explanation - made sense,

happy studying!!

7 0
2 years ago
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