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tangare [24]
3 years ago
13

There are x number of students at helms. If the number of students increases by 7.8% each year, how many students will be there

next year. Write an equation to express this.
Mathematics
1 answer:
vodomira [7]3 years ago
3 0

There will be 1.078x students next year and equation is number of students in next year = x + 7.8% of x

<h3><u>Solution:</u></h3>

Given, There are "x" number of students at helms.  

The number of students increases by 7.8% each year which means if there "x" number of students in present year, then the number of students in next year will be x + 7.8% of x

Number of students in next year = number of students in present year + increased number of students.

\begin{array}{l}{\text { Number of students in next year }=x+7.8 \% \text { of } x} \\\\ {\text { Number of students in next year }=x\left(1+\frac{7.8}{100}\right)} \\\\ {\text { Number of students in next year }=x(1+0.078)=1.078 x}\end{array}

Thus there will be 1.078x students in next year

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Maria, a biologist, is observing the growth pattern of a virus. She starts with 100 of the virus that grows at a rate of 10% per
Leni [432]
<h3>Answer: 985</h3>

=============================================

Work Shown:

A = amount after t hours

P = initial amount = 100

r = growth rate in decimal form = 0.10

t = number of hours = 24

--------

A = P*(1+r)^t

A = 100(1+0.10)^24

A = 100*(1.10)^24

A = 100*9.84973267580762

A = 984.973267580762

A = 985

5 0
3 years ago
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A small lawnmower company produced 1,500 lawnmowers in 2008. In an effort to determine how maintenance-free these units were, th
ikadub [295]

Answer:

The 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the average using the finite correction factor is:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

The information provided is:

N=1500\\n=183\\\sigma=1.47\\\bar x=3.3

The critical value of <em>z</em> for 95% confidence level is,

<em>z</em> = 1.96

Compute the 95% confidence interval for the average number of years until the first major repair as follows:

CI=\bar x\pm z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}\cdot\sqrt{\frac{N-n}{N-1}}

     =3.3\pm 1.96\times\frac{1.47}{\sqrt{183}}\times\sqrt{\frac{1500-183}{1500-1}}\\\\=3.3\pm 0.19964\\\\=(3.10036, 3.49964)\\\\\approx (3.1, 3.5)

Thus, the 95% confidence interval for the average number of years until the first major repair is (3.1, 3.5).

7 0
3 years ago
PLS HELP ME ASAP WITH 1, 2, 5, 6, 11, and 12 PLS!!
melamori03 [73]
1-

number 2) is correct





2- 3) is true



11) Jacob is not correct. because 6radical 5 is irrational



12) radical 20 is an irrational number but

so a+b is irrational



but
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so b+c is rational



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8 0
3 years ago
How do i do this.
Sonbull [250]
You have to multiply both numbers with the same factor. What I mean, 475/58 gives you 8 R 11. Now let's try this, (475x2=950) and (58x2= 116) so our new numbers are 950/116 which gives us the same answer 8 R 11 ! I hope this helped.. But let's try another one, keep in mind, you can multiply the number by any factor AS LONG AS you multiply them with the SAME factor. So if you multiply 475 by 5, then you have to multiply the 58 by 5 as well. Now let's try, (475x5=2375) and (58x5= 290) therefore, 2375/290 = which gives you 8 R 11 ! I hope I helped . I am a Palestinian student in Palestine in grade 11 and you just brought me back to grade 4 memories ! math is fun when you get it (: good luck
6 0
3 years ago
Help plzzzz and tysm &lt;3. I love you all but plz do this asap! Thank you like againnn, take you’re time!
malfutka [58]

Answer:

1.12+36=48.

2)125-25=100

3)5+100=105

4)64-30=34

7 0
3 years ago
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