3 years ago

Which of the following points is in the solution set of y > -x2 + 5? (0, 5) (1, 3) (2, 4)

Mathematics

1 answer:

mylen [45]3 years ago

5 0

Answer:

(2, 4)

Step-by-step explanation:

The only point that satisfies the inequality is (2, 4).

(0, 5) : -0^2 +5 = 5 . . . . . not > 5

(1, 3) : -1^2 +5 = 4 . . . . . . 3 is not > 4

(2, 4) : -2^2 +5 = 1 . . . . . . 4 is greater than 1, so this point is in the solution set.

You might be interested in

Algebra 1: Factoring Polynomials Factor the common factor out of each expression: 40n^4m^2+40n^3m^3-32n^3

Nina [5.8K]

Taking out the greatest common factor

GCF of 40, 40 and 32 = 8
GCF of n^4, n^3 and n^3 is n^3

so the factors are

8n^3(5nm^2 +5m^3 - 4)

7 0

3 years ago

Radical 5* radical 2

Setler [38]

Answer:

$\sqrt{10}$

Step-by-step explanation:

Rule: $\sqrt{a} \times \sqrt{b} = \sqrt{ab}$

$\sqrt{5} \times \sqrt{2} = \sqrt{5 \times 2} = \sqrt{10}$

6 0

2 years ago

Help on this question please!!!

OLga [1]

Answer:

Hello! Here is your answer

Step-by-step explanation:

112=4(28)

a=4b

You can only have one variable so:

Combine b to a:

a-b=84

4b-b=84

Divide both sides by 3:

3b/3=84/3

b=28

But that is not it:

Sum of both cards:

a+b

a=112

b=28

112+28=140

= 140

I hope I was of help. If not please let me know! Thank you! Good luck!

4 0

3 years ago

Someone please help me ASAP!!!! I really need it

MatroZZZ [7]

^ this guy is a scammer don’t click the link

7 0

3 years ago

quadrilateral kstu has vertices at (7,0) (4,-6) (0,-2) and (0,0). rotate 180 degrees around the origin

solong [7]

Step-by-step explanation:

so basically for this on u have to draw this on graph every first number of the coordinate is on x axis e.g . (7,0) 7 is on x axis and 0 is on Y axis. you can use tracing paper for this which will be more helpful as u can trace the shape and move it half way.

As u rotate it around the origin so u just turn it half way. eg I drawn it on the picture.

hope this make sense :)

5 0

3 years ago