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nexus9112 [7]
3 years ago
8

Mr. Drumm is purchasing tickets for a school museum visit. The Museum of Natural History charges a $25 group fee plus $5 per stu

dent. The Museum of Modern Art charges a group fee of $35 plus $4 per student. To pay the same amount at each museum, how many tickets will Mr. Drumm have to order?​
Mathematics
1 answer:
Greeley [361]3 years ago
4 0

Answer:

10 tickets

Step-by-step explanation:

25 + 5x = 35 + 4x

solve for x:

subtract 25 from both sides...

5x = 35 - 25 + 4x

subtract 4x from both sides...

5x - 4x = 10

x = 10, 10 tickets.

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a store owner wishes to make a new tea with a unique flavor by mixing black tea and oolong tea. if he has 35 pounds of oolong te
Verizon [17]

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the amount of black tea worth 1.80 per pound to be mixed to get the final mixture for 2.10 per pound, hence:

2.4(35) + 1.8(x) = 2.1(x + 35)

x = 35 pounds

35 pounds of black tea is needed to be mixed to get the final mixture for 2.10 per pound

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3 0
1 year ago
Solve 12^x^2+5x-4 = 12^2x+6
faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

                    12^{x^{2}+5 x-4}=12^{2 x+6}

Since the base on both sides as ‘12’ are the same, we can write it as

                     x^{2}+5 x-4=2 x+6

                     x^{2}+5 x-2 x-4-6=0

                     x^{2}+3 x-10=0

Often, the value of x is easiest to solve by a x^{2}+b x+c=0 by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For a x^{2}+b x+c=0, the values of x which are the solutions of the equation are given by:

                       x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Where, a = 1, b = 3 and c = -10

                       x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}

                       x=\frac{-3 \pm \sqrt{9+40}}{2}

                       x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}

So, the solutions for ‘x’ are

                       x=\frac{-3+7}{2}=\frac{4}{2}=2

                       x=\frac{-3-7}{2}=\frac{-10}{2}=-5

The solutions for ‘x’ are 2 and -5

6 0
2 years ago
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If 0.3 = 1 then 0.9 = 3 because 0.3+0.3+0.3=the 3.
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