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3 years ago

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The following menu items were ordered at a pizza parlor on Friday. 3 salads, 8 pizzas, 4 sides of breadsticks, and 5 pepperoni c

alzones, What is the amount of breadsticks and calzone orders the pizza parlor should expect if there were 100 total orders?

1 answer:

den301095 [7]3 years ago

6 0

Answer:

Using proportions, the pizza parlor should expect 20 breadsticks and 25 calzone orders if there were 100 total orders.

Step-by-step explanation:

Orders:

Salads 3

Pizzas 8

Sides of breadsticks 4

Pepperoni calzones 5

Total orders: 20

Proportion of sides breadsticks=4/20=0.2

Proportion of pepperoni calzones=5/20=0.25

For 100 total orders:

Sides of breadsticks=0.2(100)=20

Pepperoni calzones=0.25(100)=25

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According to an article, 47% of adults have experienced a breakup at least once during the last 10 years. Of 9 randomly select

In-s [12.5K]

Answer:

a) $P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b) $P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c) $P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=9, p=0.47)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Assuming the following questions:

a. exactly five

For this case we can use the probability mass function and we got:

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

b. at least one

For this case we want this probability:

$P(X \geq 1)$

And we can use the complement rule and we got:

$P(X \geq 1)= 1-P(X$

$P(X=0)=(9C0)(0.47)^0 (1-0.47)^{9-0}=0.0033$

And replacing we got:

$P(X \geq 1)= 1-P(X$

c. between four and six, inclusive.

For this case we want this probability:

$P(4 \leq X \leq 6)$

$P(X=4)=(9C4)(0.47)^4 (1-0.47)^{9-4}=0.257$

$P(X=5)=(9C5)(0.47)^5 (1-0.47)^{9-5}=0.228$

$P(X=6)=(9C6)(0.47)^6 (1-0.47)^{9-6}=0.135$

And adding we got:

$P(4 \leq X \leq 6)= 0.257+0.228+0.135=0.620$

6 0

3 years ago

Multiplied by 3/4 and then divided by 3/5 is the same as dividing by what?

netineya [11]

We have: x × $\frac{3}{4}$ ÷ $\frac{3}{5}$ = x × $\frac{3}{4}$ × $\frac{5}{3}$ = x × $\frac{5}{4}$ = x ÷ $\frac{4}{5}$

ANSWER: E. 4/5

Ok done. Thank to me :>

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2 years ago

Which of the following phrases are inequalities?

aev [14]

Answer:

B, C, and D

Step-by-step explanation:

They have an either a less than sign ( < ) or a greater than sign ( > ).

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3 years ago

PLEASEEE HELP MEEEE<br><br>NO LINKSSS

Artemon [7]

Answer:

$\huge\boxed{(2,\ 3);\ (-1,\ 6)}$

Step-by-step explanation:

$f(x)=x^2-2x+3\to y=x^2-2x+3\\f(x)=-x+5\to y=-x+5\\\\\left\{\begin{array}{ccc}y=x^2-2x+3&(1)\\y=-x+5&(2)\end{array}\right$

substitute (1) to (2):

$x^2-2x+3=-x+5$ add x to both sides

$x^2-2x+x+3=-x+x+5$

$x^2-x+3=5$ subtract 5 from both sides

$x^2-x+3-5=5-5$

$x^2-x-2=0\\\\x^2+x-2x-2=0\\\\x(x+1)-2(x+1)=0\\\\(x+1)(x-2)=0\iff x+1=0\ \vee\ x-2=0\\\\\boxed{x=-1\ \vee\ x=2}$

substitute the values of x to (2):

$x=-1\\\\y=-(-1)+5=1+5=6\\\\\huge\boxed{(-1,\ 6)}\\\\x=2\\\\y=-2+5=3\\\\\huge\boxed{(2,\ 3)}$

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3 years ago

Which expression is equivalent to 8g + 2 + 4g − 2 − 2g?

LekaFEV [45]

Answer:

B) 10g

Step-by-step explanation:

Collect like terms

8g + 4g - 2g = 10g

2 - 2 = 0

10g + 0= 0

4 0

2 years ago