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butalik [34]
3 years ago
14

Tiffany wants to illustrate the homework times she and some of her friends spent one night on one subject. Her goal is to show t

he range of times and be able to find the mean, median, and mode of all of the times. What would have been a better data display to use?
line graph
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0
My best guess is a line graph because it shows the consistent numbers and then you can lay them all out after you have completed the graph
garri49 [273]3 years ago
4 0
I said stem-and-leaf plot since that deals with median mode and mean
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Erik is performing a marble experiment in math class. His teacher places an equal number of black, red, and white marbles in a b
tino4ka555 [31]

Answer:

hay luluu it's me off tic tok I'm on my other account and go with c then if not that then it's b

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2 years ago
What is the volume in cubic meters of 18 MM
9966 [12]
1944 mm Please mark as brainliest if im correct
3 0
3 years ago
Please help
katrin2010 [14]
\dfrac{n^2+3n+2}{n^2+6n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n^2+2n+n+2}{n^2+4n+2n+8}-\dfrac{2n}{n+4}\\\\=\dfrac{n(n+2)+1(n+2)}{n(n+4)+2(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{(n+2)(n+1)}{(n+2)(n+4)}-\dfrac{2n}{n+4}\\\\=\dfrac{n+1}{n+4}-\dfrac{2n}{n+4}=\dfrac{n+1-2n}{n+4}=\dfrac{1-n}{n+4}

Answer:\ \boxed{B.\ \dfrac{1-n}{n+4}}
7 0
3 years ago
A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
Determine whether the following events are mutually exclusive:
Harman [31]

Answer:

non mutually exclusive event

Step-by-step explanation:

im not sure on this tho

3 0
3 years ago
Read 2 more answers
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