X + y2 = 25 x + 3y = 33
1 answer:
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Answer:
Domain {x : x > 1}
Range {y : y ∈ R}
Vertical asymptote x = 0
x-intercept (1, 0)
End behavior consistent
Graph attached down
Step-by-step explanation:
Let us study the equation:
∵ y = log(x)
→ It is a logarithmic function, so no negative values for x
∴ Its domain is {x : x > 1}
∴ Its range is {y : y ∈ R}, where R is the set of the real numbers
→ An asymptote is a line that a curve approaches, but never touches
∵ x can not be zero
∴ It has a vertical asymptote whose equation is x = 0
→ x-intercept means values of x at y = 0, y-intercept means
values of y at x = 0
∵ x can not be zero
∴ There is no y-intercept
∵ y can be zero
∴ The x-intercept is (1, 0)
→ The end behavior of the parent function is consistent.
As x approaches infinity, the y-values slowly get larger,
approaching infinity
∵ y = log(x) is a parent function
∴ The end behavior is consistent
→ The graph is attached down
Answer:
A
Step-by-step explanation:
Discriminant is given by
If it is negative then in quadratic formula the square root part becomes negative which makes the solution complex.
so there cannot be any real solution if the Discriminant is negative or less than 0 ,
The correct option for the given question is
A