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adoni [48]
3 years ago
6

If function ghas the factors (x-7) and (x + 6), what are the zeros of function ?

Mathematics
1 answer:
Darya [45]3 years ago
3 0

The zeros of function g are 7 and -6

<em><u>Solution:</u></em>

Given that function g has factors (x - 7) and (x + 6)

<em><u>To find: zeros of function</u></em>

The factor theorem is a theorem linking factors and zeros of a polynomial

The Factor Theorem states that  (x – a) is a factor of the polynomial f(x) if and only if f(a) = 0

That is, g(c) = 0 if and only if x - c is a factor

Since g(x) = (x - 7)(x + 6) then g(7) = 0 and g( -6 ) = 0

Since those two x values output 0, then those x values are called the zeros

[ g(7) = (7 - 7)(7 + 6) = 0 and g(-6) = (-6 - 7)(-6 + 6) = 0]

Thus the zeros of function g are 7 and -6

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What is the quotient of m and 7
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m/7

Step-by-step explanation:

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3 years ago
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Convert the complex number z = 4 - 10i from rectangular form to polar form.​
mrs_skeptik [129]

ANSWER

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

EXPLANATION

The polar form of a complex number ,

z = x + yi

is given by:

z = r( \cos( \theta)  + i \sin( \theta) )

where

r =  \sqrt{ {x}^{2} +  {y}^{2}  }

The given complex number is:

z = 4 - 10i

r =  \sqrt{ {4}^{2}  +  {( - 10)}^{2} }

r =  \sqrt{16  + 100}

r =  \sqrt{116}  = 2 \sqrt{29}

And

\theta=  \tan^{ - 1}(\frac{ y}{x} )

\theta=  \tan^{ - 1}(\frac{  - 10}{4} )

\theta=  292 \degree

Hence the polar form is :

r = 2 \sqrt{29} ( \cos(292 \degree)  + \sin(292 \degree))

6 0
3 years ago
My brain stopped. I need help
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Answer:

x = 99°

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Step-by-step explanation:

For Cyclic quadrilateral, the sum of the opposite angles = 180°

Let's find x :-

x + 81° = 180°

x = 180 - 81

x = 99°

Let's find y :-

y + 89° = 180°

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Hope this helps you !

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