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lions [1.4K]
3 years ago
5

Solve and show work.3a-4a+9=-12a+43-6a

Mathematics
2 answers:
SCORPION-xisa [38]3 years ago
8 0

A=2

First simplify

Regroup terms

Simplify

Subtract 9

Simplify

Addc18a

Simplify

Divide both side by 17

Simplify 34/17

Lesechka [4]3 years ago
7 0
3a-4a+9=-12a+43-6a
-a+9=-12a+43-6a
-a+9=-18a+43
-a+9+18a=43
17a+9=43
17a=43-9
17a=34
a=34:17
a=2

The answer is: a=2
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Find the value of x.
faust18 [17]

Answer:

          7 sqrt(3) =x

Step-by-step explanation:

We know that sin 60 = opposite / hypotenuse

                       sin 60 = x/14

Multiply both sides by 14

                          14 sin 60 = x

                        14 * (sqrt(3)/2) =x

                      7 sqrt(3) =x

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4 years ago
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Which expression equals a number that is NOT a rational number?
Leviafan [203]

Answer:

The correct answer would be 2π x 2²/5

Step-by-step explanation:

First, calculate the product, and evaluate the power which would be 2³π/5 and the solution is in an alternate form, therefore making it rational. :)

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3 years ago
which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2
notka56 [123]

Use\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\left(\dfrac{2}{3}\right)^4=\dfrac{2^4}{3^4}=\dfrac{16}{81}\ :)\\\\\left(\dfrac{16}{3}\right)^4=\dfrac{16^4}{3^4}=\dfrac{16^4}{81}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{81}\right)^2=\dfrac{4^2}{81^2}=\dfrac{16}{81^2}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{9}\right)^2=\dfrac{4^2}{9^2}=\dfrac{16}{81}\ :)

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3 years ago
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If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is _.
defon

Answer: If 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.

Step-by-step explanation:

  • We know that when a complex number z=a+ib is a root of a polynomial with degree 'n' , then the conjugate of the complex number (\overline{z}=a-ib) is also a root of the same polynomial.

Given: 7+5i is a zero of a polynomial function of degree 5 with coefficients

Here, 7+5i is a complex number.

So, it conjugate (\overline{7+5i}=7-5i) is also a zero of a polynomial function.

Hence, if 7+5i is a zero of a polynomial function of degree 5 with coefficients, then so is <u>its conjugate 7-i5</u>.

8 0
3 years ago
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