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dem82 [27]
3 years ago
8

How many rational numbers are between -6 and -5​

Mathematics
1 answer:
Elden [556K]3 years ago
3 0

Answer:

An infinite number.

Step-by-step explanation:

There are many, many rational fractions between -6 and -5.

For example, take the numbers - 5 2/7  and - 5 4/7. there is another rational between these  - 5 3/7.

Then we have another  between - 5 2/7 and - 5 3/7 which is - 5 5/14, - and we could go on doing this all day and never coming to an end!!

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ryzh [129]

Answer:

that is so much work um. i believe you have to graph first and look at the given problems

8 0
3 years ago
Answer with your best ability ​
yKpoI14uk [10]

Answer:

hi hi hi hi hi hi hi hi hi hi hi h

Step-by-step explanation:

hi hih uhjuhhsus

8 0
3 years ago
NEED answer pls ,dont understand hope someone can help it is multiple choice except 12,13,14,15
myrzilka [38]

Answer:

C.) Corresponding; B.) m<6 = m<2; and for the last one you probably have to divide so perhaps it might be 30 .

Step-by-step explanation:

5 0
3 years ago
PLSSSS HELLLPPPPPPP How much would it cost to buy 3.4 pounds of Bartlett pears and 2.1 pounds of Concorde pears? Concorde pears
kirill [66]

Answer:

$13.10

Step-by-step explanation:

Concard    $3.00  2.1    $6.30

Osband    $3.00  

Green Anjou  $4.00  

Bartlett          $2.00  3.4     $6.80

Red Anjou  $5.00  

                TOTAL =      $13.10

5 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
4 years ago
Read 2 more answers
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