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3 years ago

What is the value of 8!? 8 64 512 40,320 Will mark correct answer as brainliest

Mathematics

2 answers:

RUDIKE [14]3 years ago

6 0

8! is 40320 as per my calculations

steposvetlana [31]3 years ago

6 0

40320 i think is correct

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Answer asap

Gnom [1K]

Swap the n with the 7

7-5

Find the answer to 7-5

7-5=2

So the answer is 2

7 0

1 year ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

-8x^2+4x+5=0 using quadratic formula

daser333 [38]

So you want to solve for x?

It would be nice if this would easily factor:
(-4x + 5)(2x +1) = 0    This will not work!

So you need to use the quadratic formula:
a = -8, b = 4, c = 5

$x = \frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

x = (-4 +/- $\sqrt{16-4(-8)(5)}$ )/2(-8)
   = (-4 +/- $\sqrt{16 + 160}$ )/-16
   = (-4 + $\sqrt{176}$ )/-16
   = 1/4 - $\sqrt{11}$ /4

6 0

2 years ago

Jose purchases 80 shares of mutual fund with an NAV of $2. How much does this purchase cost

madreJ [45]

Answer:

idk

Step-by-step explanation:

sry

3 0

2 years ago

What is 2.85 as a fraction in simplest form

Marysya12 [62]

2.85 = 2 17/20 - hope it helps!

8 0

2 years ago

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