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torisob [31]
3 years ago
14

9 4/5 as a decimal help out plz

Mathematics
2 answers:
Helen [10]3 years ago
5 0

9 4/5 as a decimal is 9.8

goblinko [34]3 years ago
5 0
Answer: 9.8

Explanation: So first you divide the fraction by its top number by its bottom number and that would be 0.8, and for the 9, the whole number stays as the whole number in the decimal so then it would be 9.8
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Svet_ta [14]

Answer:

x ≤ 2

Step-by-step explanation:

3 0
3 years ago
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What are the first three terms of the sequence modeled by the recursive function an=1/2an-1 when a1=1?
loris [4]

Answer:

Option A is correct that is 1,\frac{1}{2},\frac{1}{4}

Step-by-step explanation:

We have been given a formula a_n=\frac{1}{2}\cdot a_n-1

a_1=1

We will put values of n in a_n=\frac{1}{2}\cdot a_n-1

when n=2 we get

a_2=\frac{1}{2}\cdot a_2-1

\Rightarrow a_2=\frac{1}{2}\cdot a_1

\Rightarrow a_2=\frac{1}{2}\cdot 1

\Rightarrow a_2=\frac{1}{2}

when n=3

a_3=\frac{1}{2}\cdot a_2

\Rightarrow a_3=\frac{1}{2}\cdot \frac{1}{2}

\Rightarrow a_3=\frac{1}{4}

Therefore, Option A is correct that is 1,\frac{1}{2},\frac{1}{4}

6 0
3 years ago
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Suppose the sediment density (g/cm3 ) of a randomly selected specimen from a certain region is known to have a mean of 2.80 and
Irina18 [472]

Answer:

0.918 is the probability that the sample average sediment density is at most 3.00

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 2.80

Standard Deviation, σ = 0.85

Sample size,n = 35

We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.85}{\sqrt{35}} = 0.1437

P(sample average sediment density is at most 3.00)

P( x \leq 3.00) = P( z \leq \displaystyle\frac{3.00 - 2.80}{0.1437}) = P(z \leq 1.3917)

Calculation the value from standard normal z table, we have,  

P(x \leq 3.00) = 0.918

0.918 is the probability that the sample average sediment density is at most 3.00

4 0
3 years ago
F(x)=3x^2+5
Westkost [7]

Answer:

2 {x}^{2}  + x - 1

7 0
3 years ago
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If 20 oz bottle marked X were to go sale. What would the new price need to be for it to be equal value to the 16 oz bottle ? Wer
zubka84 [21]

Answer:

$1.375 ≈ $1.38

Step-by-step explanation:

First, set up a proportion:

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Then, cross-multiply and solve for x:

(16)(x)=(20)(1.10)\\16x=22\\x=\frac{22}{16}\\x=1.375

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4 years ago
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