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3 years ago

11

2s and 2pz

1 answer:

noname [10]3 years ago

6 0

Do you have a picture instead of writing

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20 points! Help please

Olin [163]

Answer: 2N2O3 -> 2N2 + 3O2

Explanation:

5 0

3 years ago

Read 2 more answers

For a compound with a molecular formula of C11H20O2, what is the formula mass?

solong [7]

The molecular formula of the compound is - C₁₁H₂₀O₂
formula mass is the sum of the products of the relative atomic masses of the elements by the number of atoms of the corresponding element
r.a.m -relative atomic mass
the elements making up the compound with their relative atomic masses are;
C - 12 r.a.m - 11 C atoms
H - 1 r.a.m - 20 H atoms
O - 16 r.a.m - 2 O atoms
the formula mass- (11 x r.a.m of C ) + (20 x r.a.m of H ) + ( 2 x r.a.m of O)
formula mass = (11 x 12) + (20 x 1) + (2 x 16)
= 132 + 20 + 32
= 184
formula mass of compound is 184

3 0

4 years ago

What happens as thermal energy is transferred from the core to the mantle

musickatia [10]

It gets hotter because the core is the outside of the eath and the mantel is the more inside/hope i helped

7 0

3 years ago

At particular temperature, Kp = 70.9 for the following reactionN2O4(g) == 2NO2(g)1. A certain pressure of N2O4 is initially adde

elixir [45]

Answer : The partial pressure of $NO_2$ is, 12.34 atm

Explanation :

For the given chemical reaction:

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

The expression of $K_p$ for above reaction follows:

$K_p=\frac{(P_{NO_2})^2}{P_{N_2O_4}}$ ........(1)

The equilibrium reaction is:

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial x 0

At eqm (x-y) 2y

Putting values in expression 1, we get:

$70.9=\frac{(2y)^2}{(x-y)}$ ..............(2)

As we are given that, 25.8 % of $N_2O_4$ remains at equilibrium. That means,

$25.8\% \times x=(x-y)$

$\frac{25.8}{100}\times x=(x-y)$

$0.258\times x=(x-y)$

$0.742x=y$ ..............(3)

Now put equation 3 in 2, we get the value of 'x'.

$70.9=\frac{(2\times 0.742x)^2}{(x-0.742x)}$

$x=8.31$

Now put the value of 'x' in equation 3, we get:

$0.742x=y$

$0.742\times 8.31=y$

$y=6.17$

Now we have to calculate the new partial pressure of $NO_2$ at equilibrium.

Partial pressure of $NO_2$ = (2y) = (2\times 6.17) = 12.34 atm

Hence, the partial pressure of $NO_2$ is, 12.34 atm

8 0

3 years ago

What is the pOH of a solution that has a hydronium ion concentration [H3O+] of 8.26 x 10–5 M?

kirill115 [55]

Answer:

9.92

Explanation:

Since we are given the concetration of H+ we can find the ph by taking the negative log and then subtracting the ph from 14 to give us pOH

-log(8.26e-5) = pH= 4.08

pOH= 14-4.08

pOH= 9.92

8 0

3 years ago