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3 years ago

What happens as thermal energy is transferred from the core to the mantle

Chemistry

1 answer:

musickatia [10]3 years ago

7 0

It gets hotter because the core is the outside of the eath and the mantel is the more inside/hope i helped

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HELPPPPPPPPP ASAPPPP!!!!!

andreev551 [17]

Answer :
B

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8 0

3 years ago

What are the concentrations of A , A, B , B, and C C at equilibrium if, at the beginning of the reaction, their concentrations a

Elenna [48]

The question is incomplete, here is the complete question:

A reaction

$A+B\rightleftharpoons C$

has a standard free-energy change of -4.88 kJ/mol at 25°C

What are the concentrations of A, B, and C at equilibrium if at the beginning of the reaction their concentrations are 0.30 M, 0.40 M and 0 M respectively?

Answer: The equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

Explanation:

Relation between standard Gibbs free energy and equilibrium constant follows:

$\Delta G^o=-RT\ln K_c$

where,

$\Delta G^o$ = Standard Gibbs free energy = -4.88 kJ/mol = -4880 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = $8.314J/K mol$

T = temperature = $25^oC=[273+25]K=298K$

$K_c$ = equilibrium constant of the reaction

Putting values in above equation, we get:

$-4880J/mol=-(8.3145J/Kmol)\times 298K\times \ln K_c\\\\K_c=7.17$

We are given:

Initial concentration of A = 0.30 M

Initial concentration of B = 0.40 M

Initial concentration of C = 0 M

The chemical reaction follows:

$A+B\rightleftharpoons C$

Initial: 0.30 0.40 0

At eqllm: 0.30-x 0.40-x x

The expression of equilibrium constant for the above reaction follows:

$K_c=\frac{[C]}{[A][B]}$

We are given:

$K_c=7.17$

Putting values in above equation, we get:

$7.17=\frac{x}{(0.30-x)\times (0.40-x)}\\\\x=0.183,0.657$

Neglecting the value of x = 0.657, because change cannot be greater than the initial concentration

So, equilibrium concentration of A = $(0.30-x)=(0.30-0.183)=0.117M$

Equilibrium concentration of B = $(0.40-x)=(0.40-0.183)=0.217M$

Equilibrium concentration of C = $x=0.183M$

Hence, the equilibrium concentrations of A, B and C are 0.117 M, 0.217 M, 0.183 M respectively.

5 0

3 years ago

can the list below. Which did you include in your answer? Foam is a colloid. Colloids include gas dispersed in a liquid. Colloid

VikaD [51]

Answer:

Its all of them

Explanation:

4 0

3 years ago

Read 2 more answers

000 atm of dry nitrogen, placed in a container having a pinhole opening in its side, leaks from the container 3.55 times faster

Ivanshal [37]

We will assume that the question is discussing 1.000 atm of N₂ initially. The question is discussing diffusion rates of two gases and asks us to identify the species. We can use Graham's Law to attempt this problem with the following formula:

Rate₁/Rate₂ = sqrt(M₂/M₁)

We are told that the N₂ is 3.55 times as fast as the unknown species, so rate 1 = 3.55 and rate 2 = 1. We know the molecular weight of N₂ as 28 g/mol. Now we can use the equation above to solve for the molecular weight of the unknown, M₂:

3.55/1 = sqrt(M2/28)
(3.55)² = M₂/28
M₂ = 28 (3.55)₂
M₂ = 353 g/mol

The unknown compound has a molecular mass of roughly 353 g/mol and this is very close to the molecular mass of UF₆ which is 352.02 g/mol. Therefore, it is likely that the unknown gas is UF₆.

7 0

4 years ago

Calculate the amount of heat required to completely sublime 28.0 g of solid dry ice (co2 at its sublimation temperature. the hea

lana66690 [7]

There is no need to do anything about the temperature, because sublimation does not involve any temperature change.

First, determine how many moles of CO2 there are. The mol. wt. of CO2 is 12 +2 x 16 = 44 g/mol.

So, 25.0 equals 25/44 = 0.568 moles

So the heat required is 0.568 mol x 32.3 KJ/mol = 18.3

4 0

3 years ago

Read 2 more answers