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Rzqust [24]
3 years ago
14

Someone answer quickA),B), and C)

Mathematics
2 answers:
Julli [10]3 years ago
8 0

Step-by-step explanation:

a. 3 1/7 b. 3 1/6 and c. 2

natima [27]3 years ago
7 0

Answer:

a is 3 and 1/7 b  is 3 and 1/6 and c is 2

Step-by-step explanation:


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kolezko [41]

Answer:

c im quessing though but i got -54.1 so i dont know

Step-by-step explanation:

6 0
2 years ago
Wich decimal number best describes the fraction 137/6
Y_Kistochka [10]
Convert the fraction to a decimal by dividing the numerator by the denominator.
22.83 (the 3 is endless) 
6 0
3 years ago
71.841 to the nearest tenth
jarptica [38.1K]
Answer:
71.8
Hope this helps!
7 0
2 years ago
Read 2 more answers
What are the new vertices of triangle ABC if the triangle is translated three units to the right and then three units downward?
DerKrebs [107]

Answer:

A=(0,-1), B=(5,0) and C=(-2,-6)

Step-by-step explanation:

If the translation is 3 units to the right then to every x coordinate we add three and to the y coordinate we subtract 3.

4 0
3 years ago
Assume that a sample is used to estimate a population proportion p. Find the 98% confidence interval for a
Vikki [24]

Answer:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

Step-by-step explanation:

Information given:

n=131 represent the sample size

\hat p=0.81 represent the estimated proportion

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 98% confidence interval the value of \alpha=1-0.98=0.02 and \alpha/2=0.01, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.326

And replacing into the confidence interval formula we got:

0.81 - 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.730

0.81 + 2.326 \sqrt{\frac{0.81(1-0.81)}{131}}=0.890

And the confidence interval would be:

0.730 \leq \p \leq 0.890

6 0
3 years ago
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