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3 years ago

Count back by one with the number 953

1 answer:

6 0

If i read it right, it would just be 1 - 953. Depending on your grade (Around 3rd grade it would just be 952) Above that would be -952

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What is the average rate of change of the function over the interval x = 0 to x = 8?

salantis [7]

Ans: The average rate of change of function = $\frac{1}{102}$ (in fraction)

Explanation:
The average rate of change of function = $\frac{f(b) - f(a)}{b - a}$

Where
b = 8 (x's upper bound)
a = 0 (x's lower bound)

$f(b) = f(8) = \frac{2*8-2}{5*8-6} = \frac{7}{17} \\ f(a) = f(0) = \frac{2*0-2}{5*0-6} = \frac{1}{3} \\ \frac{f(b) - f(a)}{b-a} = \frac{ \frac{7}{17} - \frac{1}{3}}{8} = \frac{1}{102}$

Hence the average rate of change of function = $\frac{1}{102}$ (in fraction)

5 0

3 years ago

(6p-6/p)•((9p^2)/2p-2)

Alekssandra [29.7K]

Answer:

27p4-27p2-12p+12/p

Step-by-step explanation:

3 0

3 years ago

Find the value of the six trig functions given the triangle below.

Y_Kistochka [10]

$\text{Here,}\\\\\text{Opposite side,}~ O = 2\\\\\text{Hypotenuse,}~ H = \sqrt 5 \\\\\text{Adjacent side,}~ A = \sqrt{5-4} = \sqrt 1 =1 ~~ ;[\text{By using Pythagorean theorem}]\\\\\\\sin \theta = \dfrac{O}H = \dfrac 2{\sqrt 5}\\\\\\\cos \theta = \dfrac{A}{H} = \dfrac{1}{\sqrt 5} \\ \\\\ \tan \theta = \dfrac{O}{A} = \dfrac 21 = 2$

$csc \theta = \dfrac{1}{\sin \theta} = \dfrac{\sqrt 5}2\\\\\\\sec \theta = \dfrac{1}{\cos \theta} = \sqrt 5 \\\\\\\cot \theta = \dfrac 1{\tan \theta} = \dfrac 12$

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3 years ago

4p + 8 - 3p - 2

kozerog [31]

Well that friend should write p + 6 after combining like terms and simplifying

6 0

2 years ago

The actual volumes of soda in quart-sized bottles can be described by a Normal model with a mean of 32.3 fluid ounces and a stan

VLD [36.1K]

Answer:The percentage of bottles expected to have a volume less than 32 or is 40.13%

Step-by-step explanation: The volumes of soda in quart soda bottles can be represented by a Nomal model with a= 32.3 oz

b=1.2 oz

Let S be the volume of randomly selected soda bottles

Y-score: S-a/b

For S=32 oz

Substitute the values of S,a and b into the equation

Y=32-32.3/1.2

Y=-0.25

Probability of bottles that have a volume less than 32 oz is

P(S<32)=P(Y<-025)= 0.40129

Percentage of bottles that have volume less than 32 oz will be

0.40127×100%=40.13%

5 0

3 years ago