Question

Solve this system algebraically. 7x - 2y = 4 5y +3x =10

Answer 1

Answer:

x = $\frac{40}{41}$

y = $\frac{58}{41}$

Step-by-step explanation:

A system of two equation with two variables is given.

We solve it by eliminating one variable first.

The equations are:

$7x - 2y = 4 \hspace{20mm} \hdots (1)$ and

$3x + 5y = 10 \hspace{20mm} \hdots (2)$

We can eliminate either x or y.

We will eliminate y.

To do that multiply Equation (1) by 5 and Equation (2) by 2.

We get: $35x - 10y = 20$ and

$6x + 10y = 20$

Adding these two equations, we get:

$35x + 6x = 40$

$\implies 41x = 40$

⇒ x = 40/41

We substitute the value of 'x' in Equation (1) (Can be substituted in Equation (2) as well). We get:

2y = 7x - 4

⇒ 2y = $7(\frac{40}{41}) - 4$

$\implies y = \frac{140 - 82}{41}$

$\implies y = \frac{58}{41}$

Therefore, (x, y) = (40/41, 58/41).

Answer 2

Answer:The correct answer to this problem is letter D {(40/41, 58/41})

Step-by-step explanation:

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