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3 years ago

Find the measure of angle A

Mathematics

1 answer:

kow [346]3 years ago

8 0

Answer:

A=45

Step-by-step explanation:

If you take a pencil and put it in the middle of the line it looks like it could be half of the other side

180-45=135

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The sum of four times a number and negative three is twelve. What is the number?

vlabodo [156]

4(2n+3)=128n + 12=128n = 0 n = 0

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3 years ago

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Nadusha1986 [10]

Answer:

She might be needing privacy

Step-by-step explanation:

Just give it a little time if you see other signs then that is when you should be worried dont stress it right now

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4 years ago

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Find the point P on the graph of the function y=√x closest to the point (9,0)

Sphinxa [80]

Answer:

$\displaystyle \frac{17}{2}$ .

Step-by-step explanation:

Let the $x$ -coordinate of $P$ be $t$ . For $P\!$ to be on the graph of the function $y = \sqrt{x}$ , the $y$ -coordinate of $\! P$ would need to be $\sqrt{t}$ . Therefore, the coordinate of $P \!$ would be $\left(t,\, \sqrt{t}\right)$ .

The Euclidean Distance between $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ is:

$\begin{aligned} & d\left(\left(t,\, \sqrt{t}\right),\, (9,\, 0)\right) \\ &= \sqrt{(t - 9)^2 +\left(\sqrt{t}\right)^{2}} \\ &= \sqrt{t^2 - 18\, t + 81 + t} \\ &= \sqrt{t^2 - 17 \, t + 81}\end{aligned}$ .

The goal is to find the a $t$ that minimizes this distance. However, $\sqrt{t^2 - 17 \, t + 81}$ is non-negative for all real $t\!$ . Hence, the $\! t$ that minimizes the square of this expression, $\left(t^2 - 17 \, t + 81\right)$ , would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ .

Differentiate $\left(t^2 - 17 \, t + 81\right)$ with respect to $t$ :

$\displaystyle \frac{d}{dt}\left[t^2 - 17 \, t + 81\right] = 2\, t - 17$ .

$\displaystyle \frac{d^{2}}{dt^{2}}\left[t^2 - 17 \, t + 81\right] = 2$ .

Set the first derivative, $(2\, t - 17)$ , to $0$ and solve for $t$ :

$2\, t - 17 = 0$ .

$\displaystyle t = \frac{17}{2}$ .

Notice that the second derivative is greater than $0$ for this $t$ . Hence, $\displaystyle t = \frac{17}{2}$ would indeed minimize $\left(t^2 - 17 \, t + 81\right)$ . This $t\!$ value would also minimize $\sqrt{t^2 - 17 \, t + 81}\!$ , the distance between $P$ $\left(t,\, \sqrt{t}\right)$ and $(9,\, 0)$ .

Therefore, the point $P$ would be closest to $(9,\, 0)$ when the $x$ -coordinate of $P\!$ is $\displaystyle \frac{17}{2}$ .

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3 years ago

How many times larger than 2x10^3 is 6x10^6?

Zielflug [23.3K]

Answer: 5,998,000

Step-by-step explanation:

2x10^3= 2,000

6x10^6= 6,000,000

In translation, Use 1 x The Initial SIG FIGS, or first numbers. 10x10 is 100, and notice how 10 and 10 have 2 zeros, so 1x1 = 1 +00 is a way to construct the number.

In this case, the 10^x, the x can represent the number of zeros after our first value.

So, 6 + six zeros, or 6,000,000

and, 2 + 3 zeros, or 2,000

To find the difference, subtract the numbers from eachother and extract the absolute value, (meaning the final answer won't be negative).

So, 6,000,000 - 2,000 = 5,998,000, which is the answer to the prompt!

Hope this Helped!

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3 years ago

How are variables use to show relationship??

Irina-Kira [14]

A cause and effect relationship between two variables, A and B, is written A then B, or in formal logic: A => B (A implies B).

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3 years ago