It is expected to depreciate from 4400 to 800 in 6 years. The depreciation per year is the ratio
depreciation per year = (total depreciation) / (number of years)
The total depreciation is the change in value, so the depreciation per year is
(4400 - 800)/6 = 600
Karen expects the vehicle to depreciate by 600 each year.
Answer:
numbers
Step-by-step explanation:
numbers
The picture is not clear. let me assume
y = (x^4)ln(x^3)
product rule :
d f(x)g(x) = f(x) dg(x) + g(x) df(x)
dy/dx = (x^4)d[ln(x^3)/dx] + d[(x^4)/dx] ln(x^3)
= (x^4)d[ln(x^3)/dx] + 4(x^3) ln(x^3)
look at d[ln(x^3)/dx]
d[ln(x^3)/dx]
= d[ln(x^3)/dx][d(x^3)/d(x^3)]
= d[ln(x^3)/d(x^3)][d(x^3)/dx]
= [1/(x^3)][3x^2] = 3/x
... chain rule (in detail)
end up with
dy/dx = (x^4)[3/x] + 4(x^3) ln(x^3)
= x^3[3 + 4ln(x^3)]
Answer:
Step-by-step explanation:
Change the 2/3 to 4/6
Now the ratio becomes 3:4:6
So the number of each is
3x + 4x + 6x = 520
13x = 520
x = 40
Red = 3*40 = 120
Yellow = 4*40 = 160
Blue = 6 * 40 = 240
Total = 520
The box plot that would confirm the inference that Linda made would have a minimum value of 20 and a maximum value of 40. Somewhere in the between is the mean. The box plot should have a confidence interval of 95% in order to have the inference valid.<span />
