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3 years ago

5

Karen purchased a used vehicle that depreciates under a straight line method the initial value if the car is 4400 and the salvag

e value is 800 if the car is expected to have a useful life of another six years how much will it depreciate each year

2 answers:

lisov135 [29]3 years ago

8 0

Answer:

600 is the APEX answer

emmasim [6.3K]3 years ago

4 0

It is expected to depreciate from 4400 to 800 in 6 years. The depreciation per year is the ratio
depreciation per year = (total depreciation) / (number of years)

The total depreciation is the change in value, so the depreciation per year is
(4400 - 800)/6 = 600

Karen expects the vehicle to depreciate by 600 each year.

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It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an

Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that $n = 200, \pi = \frac{122}{200} = 0.61$ .

We want to build an 80% CI, so $\alpha = 0.20$ , z is the value of Z that has a pvalue of $1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667$

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0

2 years ago

To two decimal places,<br> √70<br> must lie between ____<br> and _____.

Verdich [7]

Answer:

between 8.36 and 8.37

Step-by-step explanation:

$\sqrt{70} =8.3666$

Hope this helps

3 0

1 year ago

If f(x) =69-15x then f(f^-1(x))

xenn [34]

If f(x)=69-15x then $f(f^{-1}(x))=x$

Given :

$f(x)=69-15x\\$

Lets find out $f^{-1}(x)$ . The steps to find out f inverse are

Replace f(x) by y

$y=69-15x\\Interchange \; the \; variables\\x=69-15y\\solve \; for \; y\\x-69=-15y\\Divide \; by \; -15\\\frac{-x+69}{15} =y\\Replace \;y \;with \; f^{-1}\\f^{-1}=\frac{-x+69}{15}$

Now we find $f(f^{-1}(x))$

Replace inverse function in the place of x in f(x)

$f(f^{-1}(x))=f(\frac{-x+69}{15} )=69-15(\frac{-x+69}{15})=69-(-x+69)=69+x-69=x\\f(f^{-1}(x))=x$

Learn more :

brainly.com/question/11242094

8 0

2 years ago

The table shows the minutes students spent studying for their history exam and the scores they received.

Novosadov [1.4K]

Is there a graph maybe post a picture??

6 0

2 years ago

UCF is a major Metropolitan University located in Orlando Florida. UCF is advertising their bachelor in Economics with the stati

Arlecino [84]

Answer:

The claim is rejected

Step-by-step explanation:

Claim: UCF is advertising their bachelor in Economics with the statistic that the starting salary of a graduate with a bachelor in economics is $ 48,500 according to Payscale (2013-13).

Null hypothesis: $H_0: \mu = 48500$

Alternate hypothesis : $H_a : \mu \neq 48500$

n = 50

Since n is more than 30 .

So we will use Z test

x=43350

Standard deviation = 15000

$Z=\frac{x-\mu}{\frac{s}{\sqrt{n}}}\\Z=\frac{43350-48500}{\frac{15000}{\sqrt{50}}}\\Z=-2.42$

Refer the z table

p value = 0.00776

$\alpha = 0.01$

p value < $\alpha$

So, We are failed to accept null hypothesis

Hence The claim is rejected

5 0

3 years ago