2cosx=2sin2x. Sin2x is an identity for 2sinxcos. So 2[2sinxcosx] gives you 4sinxcosx. 2cosx=4sinxcosx. Divide 2cosx on both sides and gives you 2sinx=0 and divide again, sinx=0. Sinx is 0 at 0 and 360 degrees, or pi and 2pi. So thats what x would be. 0,360,pi,2pi.
OK well take out the 6 for the first form
= 6(2x^2 + x + 4)
Also we can factor the first 2 terms to give the second form:-
= 6x(2x + 1) + 24
Answer:
1) x=z-m
3) x=g-c
5) a=u-k
7) x=u+k
9) x=k-w+v
11) x=d+r-c
13) a=p-n+m
2) a=g+c
4) a=z/m
6) a=u/k
8) x=v+w/k
10) x=m-y-z
12) a=r-d/c
14) x=w-v/k
Step-by-step explanation:
(-5,-1)
Would be ur answer!!
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