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pashok25 [27]
4 years ago
14

An aquarium is 18 in. high, 12 in. wide, and 24 in. long. How much water can the aquarium hold? (V = lwh) A) 1,872 in.3 B) 2,592

in.3 C) 5,184 in.3 D) 54 in.3
Mathematics
2 answers:
Liono4ka [1.6K]4 years ago
8 0
Its C because the 18in is the height, the 12in is the width, the 24in is the length. Which you just multiply together.
nexus9112 [7]4 years ago
3 0

Answer:

Option (c) is correct

The volume of aquarium is 5184 inche³

Step-by-step explanation:

Given : An aquarium is 18 in. high, 12 in. wide, and 24 in. long.

We have to find the amount of water the aquarium can hold.

Since, To find the amount of water the aquarium can hold  we have to find the volume of aquarium.

Since, aquarium is in shape of cuboid.

Volume of cuboid = length×  width × height

Given :

Height = 18 in.,

Width =12 in.,

Length = 24 in.

Thus, the volume of aquarium = length×  width × height  

Substitute, we get,

the volume of aquarium = 24 × 12 × 18

Simplify, we get,

The volume of aquarium = 24 × 12 × 18 = 5184 inche³

Thus, The volume of aquarium is 5184 inche³

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Read 2 more answers
Please please help me
Gekata [30.6K]

Answer:

\large\boxed{\dfrac{\boxed{8}}{81}}

Step-by-step explanation:

\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}

\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}

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