What you have to do is look at all the measurements (ft) and they are labeled. And some of the sides that aren't labeled have clues of what they could be. So when I added, I got 78 ft for my answer.
Answer:
Step-by-step explanation:
2ax−3<4x+5a
Step 1: Add -5a to both sides.
2ax−3+−5a<5a+4x+−5a
2ax−5a−3<4x
Step 2: Add 3 to both sides.
2ax−5a−3+3<4x+3
2ax−5a<4x+3
The answer is C.
To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients.
a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)
Now we can put this into the quadratic equation.


I'd be more than happy to help. Im a sophmore and Love math