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3 years ago

Use a bar model 20-x=6

Mathematics

1 answer:

irinina [24]3 years ago

4 0

Answer:

sdffaf

Step-by-step explanation:

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(x + 1)(x - 1)<br> I dont understand this could any1 help me

mr_godi [17]

Answer:

x^2-1

Step-by-step explanation:

you must use the distributive property

first you do x•x=x^2,

then you do x•1 and x•-1 to get x and -x and those cancel out,

the you do 1•-1=-1, then you put it together to get x^2-1

5 0

3 years ago

Read 2 more answers

Wich one is bigger 71 ounces or 4.5 pounds

balu736 [363]

Answer:

4.5 pounds. 1 pounds is = to 16 ounces. 16 x 4.5 is 72 ounces so 4.5 pounds is 1 ounce bigger.

8 0

3 years ago

8.23 A manufacturing company produces electric insulators. You define the variable of interest as the strength of the insulators

Kitty [74]

Answer:

The 95% confidence interval estimate for the population mean force is (1691, 1755).

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally.

The sample selected here is <em>n</em> = 30.

Thus, the sampling distribution of the sample mean will be normal.

Compute the sample mean and standard deviation as follows:

$\bar x=\frac{1}{n}\sum x=\frac{1}{30}\times 51702=1723.4\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{30-1}\times 232561.2}=89.55$

Construct a 95% confidence interval estimate for the population mean force as follows:

$CI=\bar x\pm z_{\alpha /2}\times\frac{s}{\sqrt{n}}$

$=1723.4\pm 1.96\times\frac{89.55}{\sqrt{30}}\\\\=1723.4\pm 32.045\\\\=(1691.355, 1755.445)\\\\\approx (1691, 1755)$

Thus, the 95% confidence interval estimate for the population mean force is (1691, 1755).

3 0

4 years ago

What is the next term in this geometric sequence<br>5/6,5/9,10/27,20/81

Ghella [55]

$a_1=\frac{5}{6};\ a_2=\frac{5}{9};\ a_3=\frac{10}{27};\ a_4=\frac{20}{81}\\\\\\q=a_2:a_1\\\\q=\frac{5}{9}:\frac{5}{6}=\frac{5}{9}\cdot\frac{6}{5}=\frac{2}{3}\\\\\\a_5=a_4\cdot q\\\\a_5=\frac{20}{81}\cdot\frac{2}{3}=\frac{40}{243}\to answer$

3 0

3 years ago

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Find the zeros of the following function, and plot them on the graph.

Svetlanka [38]

The zeros are (x+4)(x-4)(x+6)(x-3).

3 0

3 years ago

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