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3 years ago

What is the 12th term of the sequence 3,6,12,24....

Mathematics

2 answers:

Ymorist [56]3 years ago

8 0

The answer to this is:

Sati [7]3 years ago

7 0

$a_{0}$ =3

r=common ratio: 12/6=2; 6/3=2

r=2, $a_{n}$ = $2^{n-1}$ *3

plug in 12 for n:

$a_{12}$ = $2^{12-1}$ *3

$a_{12}$ = $2^{11}$ *3

$a_{12}$ =2048*3

$a_{12}$ =6144

The twelfth term in the sequence is 6144

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The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional

jolli1 [7]

Answer:

x= $\frac{16}{\sqrt[3]{2}+1 }$

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = $\frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}$

= $\frac{I}{x^2}+\frac{2I}{(16-x)^2}$

now Q' = 0

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x= $\frac{16}{\sqrt[3]{2}+1 }$

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2 years ago

12(4^3−6⋅3^2) solve please fast

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The answer is 291.72

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2 years ago

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Alexus [3.1K]

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4 0

2 years ago

Find value of p in..6p-1/3(p+1)=8(p+1/32

puteri [66]

The answer is,

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2 years ago

The reference desk of a university library receives requests for assistance. Assume that a Poisson probability distribution with

NISA [10]

Answer:

a) 0.125

b) 7

c) 0.875 hr

d) 1 hr

e) 0.875

Step-by-step explanation:l

Given:

Arrival rate, λ = 7

Service rate, μ = 8

a) probability that no requests for assistance are in the system (system is idle).

Let's first find p.

a) ρ = λ/μ

$\frac{7}{8} = 0.875$

Probability that the system is idle =

1 - p

= 1 - 0.875

=0.125

probability that no requests for assistance are in the system is 0.125

b) average number of requests that will be waiting for service will be given as:

λ/(μ - λ)

$= \frac{7}{8 - 7}$

= 7

= λ/[μ(μ - λ)]

$= \frac{7}{8(8 - 7)}$

= 0.875 hour

(d) average time at the reference desk in minutes.

Average time in the system js given as: 1/(μ - λ)

$= \frac{1}{(8 - 7)}$

= 1 hour

(e) Probability that a new arrival has to wait for service will be:

λ/μ =

${7}{8}$

= 0.875

5 0

3 years ago