The second solid is a parallelepiped.
The volume of a parallelepiped is the area of the base times the height (the perpendicular distance from the base to the top face).
Given that the second solid has the same base of the cube and the same height, then the volumes of two solids are the same.
Answer: 1000 cubic feet.
Answer:
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Step-by-step explanation:
To find : Convert
into ![\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Solution :
We convert units one by one,
![1\text{ m}^2=10.7639\text{ ft}^2](https://tex.z-dn.net/?f=1%5Ctext%7B%20m%7D%5E2%3D10.7639%5Ctext%7B%20ft%7D%5E2)
![1\text{ sec}=\frac{1}{3600}\text{ hour}](https://tex.z-dn.net/?f=1%5Ctext%7B%20sec%7D%3D%5Cfrac%7B1%7D%7B3600%7D%5Ctext%7B%20hour%7D)
![1\text{ cal}=0.003968\text{ BTU}](https://tex.z-dn.net/?f=1%5Ctext%7B%20cal%7D%3D0.003968%5Ctext%7B%20BTU%7D)
Converting temperature unit,
![^\circ C\times \frac{9}{5}+32=^\circ F](https://tex.z-dn.net/?f=%5E%5Ccirc%20C%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%2B32%3D%5E%5Ccirc%20F)
![1^\circ C\times \frac{9}{5}+32=33.8^\circ F](https://tex.z-dn.net/?f=1%5E%5Ccirc%20C%5Ctimes%20%5Cfrac%7B9%7D%7B5%7D%2B32%3D33.8%5E%5Ccirc%20F)
So, ![1^\circ C=33.8^\circ F](https://tex.z-dn.net/?f=1%5E%5Ccirc%20C%3D33.8%5E%5Ccirc%20F)
Substitute all the values in the unit conversion,
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D%5Cfrac%7B0.003968%7D%7B10.7639%5Ctimes%20%5Cfrac%7B1%7D%7B3600%7D%5Ctimes%2033.8%7D%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D%5Cfrac%7B0.003968%7D%7B0.101061%7D%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
Therefore, The conversion of unit is ![1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}](https://tex.z-dn.net/?f=1%5C%20%5Cfrac%7B%5Ctext%7Bcal%7D%7D%7Bm%5E2%5Ctimes%20sec%5Ctimes%20%5E%5Ccirc%20C%7D%3D0.03926%5Cfrac%7B%5Ctext%7BBTU%7D%7D%7Bft%5E2%5Ctimes%20hr%5Ctimes%20%5E%5Ccirc%20F%7D)
125 = 6 dimes = 60 and 13 nickles = 65
60+65= 125
Hope i was the brainliest asnwer.
Answer:
![V=45396.2\ cm^3](https://tex.z-dn.net/?f=V%3D45396.2%5C%20cm%5E3)
Step-by-step explanation:
Given that,
The dimensions of an aquarium are 61 cm long, 30.5 cm wide, and 30.5 cm high.
The tank is filled to 80% capacity with water.
We need to find the water needed for this tank.
The volume of cuboid is given by :
![V=lbh](https://tex.z-dn.net/?f=V%3Dlbh)
As it is filled to 80% capacity, so,
![V=\dfrac{80}{100}\times lbh\\\\=0.8\times 61\times 30.5\times 30.5\\\\V=45396.2\ cm^3](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B80%7D%7B100%7D%5Ctimes%20lbh%5C%5C%5C%5C%3D0.8%5Ctimes%2061%5Ctimes%2030.5%5Ctimes%2030.5%5C%5C%5C%5CV%3D45396.2%5C%20cm%5E3)
So,
of water is needed for this tank.
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