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Daniel [21]
3 years ago
13

Katherine worked a total of 60 hours a week. She was paid $4.50 an hour. How much money did she make a week

Mathematics
1 answer:
Masja [62]3 years ago
3 0
$260.00 money was made
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Urgent!!!! The scores of a high school entrance exam are approximately normally distributed with a given mean Mu = 82.4 and stan
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What is the factored form of the polynomal? x2-12x+27
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The answer is (x-9) (x-3).

Step-by-step explanation:

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When you add the like terms you get,

x^{2} - 12x +27

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Which of the following inequalities has a solution x≥−3
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Answer: A

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Find the major axis for the ellipse <br> x² + 16y2-96y + 128 = 0
Softa [21]

The major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

To answer the question, we need to write it in the standard form of the equation of an ellipse

<h3>Equation of an ellipse</h3>

The equation of an ellipse centered at  (h,k) is

(x - h)²/a² + (y - k)²/b² (1) where a > b and the major axis is parallel to the x axis

Given x² + 16y² - 96y + 128 = 0, we convert it into the standard equation of an ellipse.

So, x² + 16y² - 96y + 128 = 0

Dividing through by 16, we have

x²/16 + 16y²/16  - 96y/16 + 128/16 = 0/16

x²/16 + y² - 6y + 8 = 0

Completing the square in y by adding and subtracting (-6/2)² = (-3)²

x²/16 + y² - 6y + (-3)² - (-3)² + 8 = 0

x²/16 + (y - 3)² - 9 + 8 = 0

x²/16 + (y - 3)² - 1 = 0

x²/16 + (y - 3)² = 1

x²/4² + (y - 3)²/1² = 1  (2)

Comparing equations (1) and (2), we have that a = 4 and b = 1.

Since a = 4 > b = 1, the major axis for the ellipse is the x-axis

So, the major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

Learn more about ellipse here:

brainly.com/question/26679189

#SPJ1

8 0
2 years ago
What is the image of the point (3,2)(3,2) after a rotation of 90^{\circ}90 ∘ counterclockwise about the origin?
BARSIC [14]

Answer: = (-2,3)

Step-by-step explanation:

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Here, fixed point = origin = (0,0)

Transformation rule for rotation of  90^{\circ}counterclockwise about the origin:

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Then, the image of the point (3,2) =  (-2,3)

Hence, the image of the point (3,2) after a rotation of  90^{\circ}counterclockwise about the origin = (-2,3)

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